Can you help me to check a number is even or odd without using any conditions.
arupa 0 Newbie Poster
Ramy Mahrous 401 Postaholic Featured Poster
Can't!!
Your question has words "OR" this means you've to use a branched code...
selvaganapathy 31 Posting Pro
Can you help me to check a number is even or odd without using any conditions.
I think Bitwise & operator can be useful.
No & 2 == 0 means Odd
and
No & 2 == 2 means Even
(here No is any number)
Is this correct?
I think it also using condition but different approach rather than modulus
Alex Edwards 321 Posting Shark
I think Bitwise & operator can be useful.
No & 2 == 0 means Odd
and
No & 2 == 2 means Even
(here No is any number)Is this correct?
I think it also using condition but different approach rather than modulus
Though zero isn't an even number, it's even enough.
No & 2 == 2 would return false for No = 0.
.
.
.
Modulus wins!
selvaganapathy 31 Posting Pro
Though zero isn't an even number, it's even enough.
No & 2 == 2 would return false for No = 0.
Modulus wins!
Yes, I agree
but you can change the condition like
No & 1 == 1 means Odd
otherwise Even
Alex Edwards commented: Yes, the bitwise AND will always return true when comparing an odd number with 1 since 1 bitAND 1 is true (or 1) +3
arupa 0 Newbie Poster
}
Console.WriteLine("enter number to check even or odd");
int n=Convert.ToInt32(Console.ReadLine);
string []array=new string[]{"Even","Odd"};
Console.WriteLine(n%2);
}
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