This has me a bit stumped but I must be doing something wrong here, if you don't mind checking this for me would be greatly appreciated.
int main ()
{
int input;
cout << "Enter a positive intiger to determin if it is odd or even (-1 to cancel): ";
cin >> input;
if ( input != -1)
{
cout << "Thank you please close the program./n";
}
else if (input%2 == 0)
{
cout << "The number is Even./n";
}
else
{
cout << "The Number is Odd./n";
}
return 0;
}
Well you need a loop if you want to keep asking the user for input until they enter -1.
{
bool done = false;
while (!done){
// ask for input and do my processing
// when input is -1, set done to true and exit.
done = true;
}It's a little ambiguous what the problem is. Do you want to repeat till a -1 is entered? If so, see stilllearning's post. If the problem is that your console closes too fast to see the output and you want to keep the console open, see this thread:
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