capital letter

[singhraghav]

i am trying to take input for name and return it with only the first letters of the name as capital....i am able to it the first name but m unable to move on to the second and last name.... please help..

string ToUpper(string n)
{
           for(int i=0;i<n.length();i++)

       
     {
                
                string m = n;
                for(int i = 1; i < m.length(); i++)
                m[i] = tolower(m[i]);
     
                if (n[i] >='a' && n[i] <='z')
                
                n[i]=n[i]-32;
                
                
                
                return m;
                return n;
     }
     
      }

[ninwa]

Here's my solution: http://codepad.org/UlW4iy19

Cheers,
ninwa

[unbeatable0]

This thread may help you:
http://www.daniweb.com/forums/thread161801.html

[BeyondTheEye]

I'm supposing you're obtaining user input by using:

cin >> name;

If you are, I suggest you read this thread. The problem with cin is it only takes input till a whitespace is found, so you're only using the first word.

[singhraghav]

hey thanks guys...with ur help i have got it... but i want to make a do while loop of it...can u tell me how to that...because if the name is having an integer or any other sign i have to output an error message and then again take input

{
    string n;
    string s;
    

  cout<<"Please enter your name :"<<flush;
  getline(cin, n);
   for(int i=1; i<n.length(); i++)
 { if (n[i]<='A'|| n[i]>='z' ||n[i]!=' ')
  cout<<"Error code 01: Name contains a character that is neither an alphabet nor a space"<<endl;

}  if(n[0]>='a' && n[0]<='z') n[0]-='a'-'A';


   for(int x=1; x<n.length(); x++)
   {
            if(n[x]>='a' && n[x]<='z' && n[x-1]==' ') n[x]-='a'-'A';
             else if(n[x]>='A' && n[x]<='Z') n[x]+='a'-'A';
  }
 
 cout<<n<<endl;

[BeyondTheEye]

Version with loop:

bool Error = true;
while(Error)
{
{
string n;
string s;


cout<<"Please enter your name :"<<flush;
getline(cin, n);
for(int i=1; i<n.length(); i++)
{ if (n[i]<='A'|| n[i]>='z' ||n[i]!=' ')
{
Error = false;
cout<<"Error code 01: Name contains a character that is neither an alphabet nor a space"<<endl;
}

} if(n[0]>='a' && n[0]<='z') n[0]-='a'-'A';


for(int x=1; x<n.length(); x++)
{
if(n[x]>='a' && n[x]<='z' && n[x-1]==' ') n[x]-='a'-'A';
else if(n[x]>='A' && n[x]<='Z') n[x]+='a'-'A';
}
}

cout<<n<<endl;

[singhraghav]

hey..i have tries the while loop...but it doesnt works...can ne1 spot the prblm

int main(int argc, char *argv[])
{
    string n;
    string s;
 
 {   

  cout<<"Please enter your name :"<<flush;
  getline(cin, n);
  
  for(int i=1; i<n.length(); i++)
  while(n[i]<='A'|| n[i]>='z');
  
  cout<<"Error code 01: Name contains a character that is neither an alphabet nor a space"<<endl;
  cout<<"Please enter your name :"<<flush;
  getline(cin, n);
   if(n[0]>='a' && n[0]<='z') n[0]-='a'-'A';


   for(int x=1; x<n.length(); x++)
   {
            if(n[x]>='a' && n[x]<='z' && n[x-1]==' ') n[x]-='a'-'A';
             else if(n[x]>='A' && n[x]<='Z') n[x]+='a'-'A';
  }

 cout<<n<<endl;

}

[BeyondTheEye]

Sorry, I didn't test it before. This does work:

#include <iostream>
#include <string>

using namespace std;

int main(int argc, char *argv[])
{
    string n;
    //Removed string s; it wasn't being used...?
    bool Error = true;
    
    //Main loop added
    while(Error)
    {
        Error = false;
        cout<<"Please enter your name: "<<flush;
        getline(cin, n);

        for(int i=0; i<n.length(); i++)
            //Checking for whitespace added, your version gave an error on space
            if(n[i] != ' ' && (n[i] <= 'A' || n[i] >= 'z'))
            {
                cout<<"Error code 01: Name contains a character that is neither an alphabet nor a space"<<endl;
                Error = true;
                break;
            }

        //Only convert if the input is correct
        if(!Error)
        {
            if(n[0]>='a' && n[0]<='z')
                n[0]-='a'-'A';

            for(int x=1; x<n.length(); x++)
            {
                if(n[x]>='a' && n[x]<='z' && n[x-1]==' ') n[x]-='a'-'A';
                else if(n[x]>='A' && n[x]<='Z') n[x]+='a'-'A';
            }

            cout<<n<<endl;
        }
    }

    return 0;
}

I changed/added a few things(Placed comments). Though I suggest you try structuring your code a bit better.
I'm not sure this is what you wanted, but it appears to be..