I have a struct. I want to declare a pointer to that struct. Now I want 10 of those structs. How is this declared? I have tried (call the struct foo for example):
foo* test[10];
when I make a call to test[0]->whatever or test[5]->whatever it seems to always write to the first element (the 0th of the array).
I think what I'm getting is an array of pointers. I want a pointer to an array of structs.
How do I delare this? Thanks.
Yes, you are getting an array of pointers.
Instead, declare your array of structs:
foo test[10];
Now you have 10 foo objects and foo[0].myMember will reference the contents of the first one.
To get a pointer you then use:
foo* pFoo = &test[0];
which will give you a pointer to the first one.
Correction: you are getting an array of uninitialized pointers. Accessing them may result in undefined behaviour. So do it like MrSpigot recommends or use new to initialize the array members.
you can also do it like Jenca's second suggestion like:
foo *test;
foo = new struct foo[10];Thanks all.
MrSpigot, how would I then access the structs through the pointer?
pFoo->test[0].index = blah; does not work. How would this be done?
Thanks.
Thanks all.
MrSpigot, how would I then access the structs through the pointer?
pFoo->test[0].index = blah; does not work. How would this be done?
Thanks.
pFoo->index = blah;
will access the first struct, but more generally you could use pFoo[n].index = blah;
Or modify pFoo:
pFoo += 1;
pFoo->index = blah; // pFoo now references the second struct
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