Member Avatar for sharensla

please help me i want to make a program that implement functions and arrays using pointers.The user provides an array of integer data, while the system calculates the average ,standard deviation,and median of the array.

i am unable to convert the input data string into separate parts and save into another separate variable.the maximum number of input integers is
50.

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  • Latest Post Latest Post by sharensla

Dani AI

Generated

The thread goal was to accept up to 50 integers (entered either one-per-prompt or as a single string) and compute average, standard deviation and median while demonstrating pointer/array usage. was right that reading numbers directly is simplest; when a single-line input is required, the common gap is splitting tokens and validating them. The snippets below show a robust parse-then-stat approach that keeps pointer-based functions while using a safe, resizable container for input.

A small parser that accepts comma- or space-separated integers and stops at a maximum count:

#include <sstream>
#include <vector>
#include <string>

std::vector<int> parseLine(const std::string& line, size_t maxCount = 50) {
    std::string tmp = line;
    for (char& c : tmp) if (c == ',') c = ' ';
    std::istringstream iss(tmp);
    std::vector<int> out;
    int v;
    while (out.size() < maxCount && (iss >> v)) out.push_back(v);
    return out;
}

Pointer-based stat functions (use vec.data() and vec.size() to call them):

#include <numeric>
#include <cmath>
#include <vector>
#include <algorithm>

double mean(const int* data, size_t n) {
    return std::accumulate(data, data + n, 0.0) / n;
}

double stddev(const int* data, size_t n, bool sample = false) {
    double mu = mean(data, n);
    double sumsq = 0.0;
    for (size_t i = 0; i < n; ++i) {
        double d = data[i] - mu;
        sumsq += d * d;
    }
    double denom = n - (sample ? 1 : 0);
    return std::sqrt(sumsq / denom);
}

double median(const int* data, size_t n) {
    std::vector<int> tmp(data, data + n);
    std::sort(tmp.begin(), tmp.end());
    if (n % 2) return tmp[n/2];
    return (tmp[n/2 - 1] + tmp[n/2]) / 2.0;
}

Practical notes: always check n > 0 before calling these; for sample stddev require n > 1. Use double/long double accumulators to avoid integer truncation and overflow. Prefer std::vector or smart pointers over raw new[]/delete[] (if new[] is used, pair it with delete[]). These adjustments address the original parsing issue while keeping the pointer-based function signatures requested by the assignment.

Member Avatar for vsha041

Hi,

I don't understand why are you reading input from the user as a string ? or do you have to ? You can go like this:-

#include <iostream>

using namespace std;

int main(){
          int x = 0;
          cout<<"How many integers you want to enter ? ";
          cin>>x;

          int* arr = new int[x];
          // now calculate the average
          float average = 0.0f;
          for(int i = 0; i < x; i++){

}

}
Member Avatar for vsha041

Sorry, last post was a mistake !!!!!!!!!!

Hi,

I don't understand why are you reading input from the user as a string ? or do you have to ? You can go like this:-

#include <iostream>

using namespace std;

int main(){
          int x = 0;
          cout<<"How many integers you want to enter ? ";
          cin>>x;

          int* arr = new int[x];
          // now calculate the average
          float average = 0.0f;
          for(int i = 0; i < x; i++){
                  average = average + arr[i];
          }

         cout<<"Average is "<<average / x<<endl;
         delete x;

}
Member Avatar for sharensla

Thanx vsha041 u change my mind
i have done the whole programming task successfully i shall post the whole program later

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