i want code for the follwing series
1
1 2
1 2 3
1 2 3 4
1 2 3 4 ..................n
when we n as 2 it should display
1
1 2
when we gave n as 4 it should dispaly
1
1 2
1 2 3
1 2 3 4
i want code for the follwing series
1
1 2
1 2 3
1 2 3 4
1 2 3 4 ..................n
when we n as 2 it should display
1
1 2
when we gave n as 4 it should dispaly
1
1 2
1 2 3
1 2 3 4
The code is trivial. Try doing it yourself first before resorting to cheating.
I really unware of the code
please help me out
i m beginer of "C",
if u provide me with cide,i can develop few of that sort
pleae help me
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
printf("%d",j);
}
printf("\n");
}
Thanks for the reply
i will be using the same
thanks a lot
Thanks for the reply
i will be using the same
thanks a lot
His code isn't correct solution to your problem, but does give you a good start on it.
sorry, made a small mistake, in the inner loop, the condtion must be j<i
I wish I had a banstick right now.
#include<stdio.h>
main()
{
int i,j,n;
printf("Enter the value of n:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
printf("%d ",j);
printf("\n");
}
}
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