I have written a program that multiplies 2 decimals. My multiplication output is fine.
However I would like to do multiplication by passing in two parameters via command line. So far e.g. lets say if I just put '3 4' in the command line without the quotes.. nothing happens...
however if I put the numbers like this 'mult 3 4' -- of course without quote.. its works.. I see 12 on the console... is there anyway where I dont have to type in mult and just type '3 '4' ???
ideas???
code?
Are you trapping for a keyword mult?
How about trapping for operators
3 * 4
12
1 + 2
3
etc.
Or even
* 3 4
12
examples always help. thanks
meaning i can use an example..
Can't do that, you don't have code!
here is the code...
.data
errmsg:
.asciiz "Two command line arguments required.\n"
newline:
.asciiz "\n"
result:
.space 11
.text
.globl main
main:
move $s0, $a0
move $s1, $a1
move $s2, $zero
move $s3, $zero
move $s4, $zero
# check if two arguments are given
li $t0, 2
ble $a0, $t0, error
# parse the first number
lw $a0, 4($s1)
jal atoi
move $s2, $v0
# parse the second number
lw $a0, 8($s1)
jal atoi
move $s3, $v0
# multiply the numbers
mult $s2, $s3
mflo $s4
# format the result
la $a0, result
move $a1, $s4
jal itoa
# print the result
li $v0, 4
la $a0, result
syscall
li $v0, 4
la $a0, newline
syscall
b exit
error:
# print error message
li $v0, 4
la $a0, errmsg
syscall
exit:
li $v0, 10
li $a0, 0
syscall
atoi:
move $v0, $zero
# detect sign
li $t0, 1
lbu $t1, 0($a0)
bne $t1, 45, digit
li $t0, -1
addu $a0, $a0, 1
digit:
# read character
lbu $t1, 0($a0)
# finish when non-digit encountered
bltu $t1, 48, finish
bgtu $t1, 57, finish
# translate character into digit
subu $t1, $t1, 48
# multiply the accumulator by ten
li $t2, 10
mult $v0, $t2
mflo $v0
# add digit to the accumulator
add $v0, $v0, $t1
# next character
addu $a0, $a0, 1
b digit
finish:
mult $v0, $t0
mflo $v0
jr $ra
itoa:
subu $sp, $sp, 40
sd $s0, 0($sp)
sd $s2, 8($sp)
sd $s4, 16($sp)
sd $s6, 24($sp)
sw $ra, 32($sp)
move $s0, $a0
move $s1, $a1
# print minus if the number is negative
bgez $s1, char
li $t0, 45
sb $t0, 0($s0)
addu $s0, $s0, 1
addu $a0, $a0, 1
# make the number positive
li $t0, -1
mult $s1, $t0
mflo $s1
char:
# divide number by ten
li $t0, 10
divu $s1, $t0
mflo $s1
mfhi $t0
# translate digit to character
addu $t0, $t0, 48
# write character
sb $t0, 0($a0)
# finish if quotient is zero
beqz $s1, return
# move to the next position
addu $a0, $a0, 1
b char
return:
# put null character to the end of the string
move $t0, $zero
sb $t0, 1($a0)
# reverse the string with the digits
move $a0, $s0
jal reverse
ld $s0, 0($sp)
ld $s2, 8($sp)
ld $s4, 16($sp)
ld $s6, 24($sp)
lw $ra, 32($sp)
addu $sp, $sp, 40
jr $ra
reverse:
# find the last character in the string
move $t0, $a0
next:
lbu $t1, 0($t0)
beqz $t1, last
addu $t0, $t0, 1
b next
last:
# move to the last character
subu $t0, $t0, 1
swap:
# done when pointers meet
bgeu $a0, $t0, done
# exchange characters
lbu $t2, 0($a0)
lbu $t3, 0($t0)
sb $t2, 0($t0)
sb $t3, 0($a0)
# step to the next pair
addu $a0, $a0, 1
subu $t0, $t0, 1
b swap
done:
jr $rahere is the code...
.data
errmsg:
.asciiz "Two command line arguments required.\n"
newline:
.asciiz "\n"
result:
.space 11
.text
.globl main
main:
move $s0, $a0
move $s1, $a1
move $s2, $zero
move $s3, $zero
move $s4, $zero
# check if two arguments are given
li $t0, 2
ble $a0, $t0, error
# parse the first number
lw $a0, 4($s1)
jal atoi
move $s2, $v0
# parse the second number
lw $a0, 8($s1)
jal atoi
move $s3, $v0
# multiply the numbers
mult $s2, $s3
mflo $s4
# format the result
la $a0, result
move $a1, $s4
jal itoa
# print the result
li $v0, 4
la $a0, result
syscall
li $v0, 4
la $a0, newline
syscall
b exit
error:
# print error message
li $v0, 4
la $a0, errmsg
syscall
exit:
li $v0, 10
li $a0, 0
syscall
atoi:
move $v0, $zero
# detect sign
li $t0, 1
lbu $t1, 0($a0)
bne $t1, 45, digit
li $t0, -1
addu $a0, $a0, 1
digit:
# read character
lbu $t1, 0($a0)
# finish when non-digit encountered
bltu $t1, 48, finish
bgtu $t1, 57, finish
# translate character into digit
subu $t1, $t1, 48
# multiply the accumulator by ten
li $t2, 10
mult $v0, $t2
mflo $v0
# add digit to the accumulator
add $v0, $v0, $t1
# next character
addu $a0, $a0, 1
b digit
finish:
mult $v0, $t0
mflo $v0
jr $ra
itoa:
subu $sp, $sp, 40
sd $s0, 0($sp)
sd $s2, 8($sp)
sd $s4, 16($sp)
sd $s6, 24($sp)
sw $ra, 32($sp)
move $s0, $a0
move $s1, $a1
# print minus if the number is negative
bgez $s1, char
li $t0, 45
sb $t0, 0($s0)
addu $s0, $s0, 1
addu $a0, $a0, 1
# make the number positive
li $t0, -1
mult $s1, $t0
mflo $s1
char:
# divide number by ten
li $t0, 10
divu $s1, $t0
mflo $s1
mfhi $t0
# translate digit to character
addu $t0, $t0, 48
# write character
sb $t0, 0($a0)
# finish if quotient is zero
beqz $s1, return
# move to the next position
addu $a0, $a0, 1
b char
return:
# put null character to the end of the string
move $t0, $zero
sb $t0, 1($a0)
# reverse the string with the digits
move $a0, $s0
jal reverse
ld $s0, 0($sp)
ld $s2, 8($sp)
ld $s4, 16($sp)
ld $s6, 24($sp)
lw $ra, 32($sp)
addu $sp, $sp, 40
jr $ra
reverse:
# find the last character in the string
move $t0, $a0
next:
lbu $t1, 0($t0)
beqz $t1, last
addu $t0, $t0, 1
b next
last:
# move to the last character
subu $t0, $t0, 1
swap:
# done when pointers meet
bgeu $a0, $t0, done
# exchange characters
lbu $t2, 0($a0)
lbu $t3, 0($t0)
sb $t2, 0($t0)
sb $t3, 0($a0)
# step to the next pair
addu $a0, $a0, 1
subu $t0, $t0, 1
b swap
done:
jr $raCommand line Arguments are typically passed in one of two ways to a program at startup.
int count count of arguments
char *argv[] array of arguments
This seems to be the way you're handling it, and your code seems okay.
An alternate method is a single string where arguments have to be parsed but you aren't setup that way. You can be because your AtoI function tracks where the number ended and a non-digit continues.
This is assembly code, I am recommending much more commenting then you are doing!
For example:
# _________________
# ASCIIz to signed integer
#
# (int) v0 = atoi( char * a0 )
atoi:
move $v0, $zero
# detect sign
li $t0, 1
lbu $t1, 0($a0)
bne $t1, 45, digit # (C <> '-')
# NEGATIVE
li $t0, -1
addu $a0, $a0, 1
digit:
# read character
lbu $t1, 0($a0)
# finish when non-digit encountered
bltu $t1, 48, finish # (C < '0')
bgtu $t1, 57, finish # (C > '9')
# translate character into digit
subu $t1, $t1, 48 # C -= '0'
# multiply the accumulator by ten
li $t2, 10
mult $v0, $t2
mflo $v0 # v0 = Lo result
# add digit to the accumulator
add $v0, $v0, $t1 # N = (N * 10) + A
# next character
addu $a0, $a0, 1 # advance pointer
b digit
# handle sign
finish:
mult $v0, $t0 # N *= { 1 : -1 }
mflo $v0
jr $raWe're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.