How can I do it - with pointer and only one loop ?
for exmpl function - unsigned int dif(const char *str)
counter = 0;
for(i = 0; i < N; i++)
A[i] = 0;
do
{
A[tmp % 10]++;
tmp /= 10;
}
while(tmp);
for(i = 0; i < N; i++)
if(A[i])counter++;
printf("\n\nThere r %u different digits in the number %u\n",counter , n);u dint define tmp... wat is tmp actually??
I read this posting a few times and I'm at a loss..Do you mean if you have a number say:
unsigned int myint = 87456;
do you want to extract from it 8 - 7 - 4 - 5 - 6?
No, I want like that 87456 - we have 5 different digits (It's all what I want)
one more exmp - number 113452266 - we have 6 different digts
I did it with two loops but i don't know - how to do it with 1 loop and pointers :)
No, I want like that 87456 - we have 5 different digits (It's all what I want)
one more exmp - number 113452266 - we have 6 different digts
I did it with two loops but i don't know - how to do it with 1 loop and pointers :)
so you have a number defined as
unsigned int myint = 113452266;
and you want to extract the number of unique digits from myint?
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