Xslt problem

Question

vivek4075 0 Newbie Poster

16 Years Ago

hi all,
sorry i am posting on top of this mail
i have a problem
see one xml file look like
<my-app>
<name></name>

</my-app>

i want to uncomment the commented part through xslt. please help me

thanks in advance

xml:xsl

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Latest Post 16 Years Ago Latest Post by vivek4075

Dani AI

Generated 10 Months Ago

A robust way to turn commented XML fragments into real nodes is to parse the comment text and then decide whether to emit the parsed nodes. The quick trick shown earlier (emitting comment text with disable-output-escaping) can work for simple output, but it is fragile: it only affects serialization, does not produce real element nodes in the XSLT result tree, and many processors or APIs ignore it. For a reliable, testable transform use an XSLT processor that supports parsing strings as XML (XSLT 3.0 provides this).

Example (XSLT 3.0 idea): parse the comment into a fragment, extract the inner element name, test it against the existing filters, and only then copy the parsed nodes into the result. The core looks like this:

<xsl:template match="comment()">
  <xsl:variable name="frag" select="parse-xml-fragment(.)"/>
  <xsl:variable name="mappedName" select="$frag/*/filter-name/string()"/>
  <xsl:if test="$mappedName = /my-app/filter/filter-name">
    <xsl:copy-of select="$frag/*"/>
  </xsl:if>
</xsl:template>

Notes and cautions:

The comment text must contain well-formed XML. Leading/trailing text or unescaped entities will break parsing.
parse-xml-fragment (standard in XSLT 3.0) returns nodes you can query with XPath; this makes conditional logic straightforward.
If using an older processor, look for processor-specific parse extensions (or pre-process the file to remove the comment markers before running XSLT). Avoid relying on disable-output-escaping for node-level logic.
Watch namespaces: if the commented fragment uses prefixes, the fragment must declare those namespaces or the parsed nodes will be in the wrong namespace.

This approach lets the XSLT decide, per commented fragment, whether to “uncomment” it based on actual filter-name matches. It also produces a proper result tree suitable for further XSLT processing or accurate serialization. Thanks to for the original problem report and to @MartinHonnen for the guidance the thread received.

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vivek4075 0 Newbie Poster · Answer 1 · 2010-01-08T17:53:12+00:00

<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>

<xsl:template match="comment()">
<xsl:value-of select="." disable-output-escaping="yes" />
</xsl:template>

vivek4075 0 Newbie Poster · Answer 2 · 2010-01-15T12:41:38+00:00

hi all please help me i am very new in this
see i ahve one xml file ::

<my-app>
<filter>
<filter-name>myrunclass</filtername>
<filter-class>myFirstClass</filter-class>
</filter>
<filter>
<filter-name>myCompileclass</filtername>
<filter-class>mySecondClass</filter-class>
</filter>
<filter>
<filter-name>myclass</filtername>
<filter-class>myThirdClass</filter-class>
</filter>

<filter-mapping>
<filter-name>ResponseEncodingFilter</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>

</my-app>

i need to uncomment the filter-mapping tag but based on some condition like inside <filter> if <filter-name> tag is match with commented <filter-mapping>/<filter-name> tag then we need to uncomment only those <filter-mapping> tag.

so OUTPUT become like

<my-app>
<filter>
<filter-name>myrunclass</filtername>
<filter-class>myFirstClass</filter-class>
</filter>
<filter>
<filter-name>myCompileclass</filtername>
<filter-class>mySecondClass</filter-class>
</filter>
<filter>
<filter-name>myclass</filtername>
<filter-class>myThirdClass</filter-class>
</filter>

<filter-mapping>
<filter-name>myrunclass</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>

<filter-mapping>
<filter-name>ResponseEncodingFilter</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>

</my-app>

please help me

thanks in advance

vivek4075 0 Newbie Poster · Answer 3 · 2010-01-15T19:26:50+00:00

hi all please help me i am very new in this
see i ahve one xml file ::
<my-app>
<filter>
<filter-name>myrunclass</filtername>
<filter-class>myFirstClass</filter-class>
</filter>
<filter>
<filter-name>myCompileclass</filtername>
<filter-class>mySecondClass</filter-class>
</filter>
<filter>
<filter-name>myclass</filtername>
<filter-class>myThirdClass</filter-class>
</filter>

<filter-mapping>
<filter-name>ResponseEncodingFilter</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>

</my-app>
i need to uncomment the filter-mapping tag but based on some condition like inside <filter> if <filter-name> tag is match with commented <filter-mapping>/<filter-name> tag then we need to uncomment only those <filter-mapping> tag.
so OUTPUT become like

<my-app>
<filter>
<filter-name>myrunclass</filtername>
<filter-class>myFirstClass</filter-class>
</filter>
<filter>
<filter-name>myCompileclass</filtername>
<filter-class>mySecondClass</filter-class>
</filter>
<filter>
<filter-name>myclass</filtername>
<filter-class>myThirdClass</filter-class>
</filter>
<filter-mapping>
<filter-name>myrunclass</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>ResponseEncodingFilter</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>

</my-app>
please help me
thanks in advance

i got the answer thanks a lot of you people help and thanks to Mr. Martin Honnen who gave me the solution