Hello,
I am trying to do a program that is reading for example a.txt file that have 5 lines and i want him to show me for example line #3 only, i know i need to use fgets but i rly dont know how to start it
a.txt
1;27.01.1957;8;12;31;39;43;45;
2;03.02.1957;5;10;11;22;25;27;
3;10.02.1957;18;19;20;26;45;49;
4;17.02.1957;2;11;14;37;40;45;
5;24.02.1957;8;10;15;35;39;49;Thanks for help
Read and discard lines 1 and 2, then read line 3 and you've got it.
I would open the file and read three lines into it and then display the results...This sounds like a for loop to me..
Hello,
Hmm but what if Ive got like 7k of lines is there any difference?
I will try to show you some code in sec
Hello,
Ive got something like that to show all the lines any help in it?
#include <stdio.h>
int main ()
{
FILE *f;
f = fopen ( "a.txt", "r" );
if ( f != NULL )
{
char line [ 128 ];
while ( fgets ( line, sizeof line, f ) != NULL )
{
fputs ( line, stdout );
}
fclose (f);
}
else
{
perror ( "a.txt" );
}
system("pause");
}Sorry for one post after another
Read and discard lines 1 and 2, then read line 3 and you've got it.
As in...
#include <stdio.h>
void fetch(const char *filename, int lineno)
{
char line [ 128 ];
int i;
FILE *file = fopen ( filename, "r" );
if ( file )
{
for ( i = 0; i < lineno; ++i )
{
if ( fgets ( line, sizeof line, file ) == NULL )
{
return;
}
}
fputs ( line, stdout );
fclose ( file );
}
else
{
perror ( filename );
}
}
int main ()
{
fetch ( "a.txt", 3 );
return 0;
}
/* a.txt
1;27.01.1957;8;12;31;39;43;45;
2;03.02.1957;5;10;11;22;25;27;
3;10.02.1957;18;19;20;26;45;49;
4;17.02.1957;2;11;14;37;40;45;
5;24.02.1957;8;10;15;35;39;49;
*/
/* my output
3;10.02.1957;18;19;20;26;45;49;
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