what i am trying to do here. is to let the user type a hexadecimal number

http://en.wikipedia.org/wiki/Hexadecimal

and then display it.

import java.io.*;
class Ex23
{
          public static void main(String[] args)
          {
           Console console=System.console();
           System.out.println("please type a hexadecimal number");
           String input;
           input=console.readLine();
           int number;
           int number=Integer.parseInt(input);
           int count=0;
           char c= input.charAt(0);
           c= console.readline(input);           
           String abc= "abcdef";
           
           
           if(c!=number)
             
                while(c==abc.charAt(count))
                 {
                 number2=count+9;
                 count++;}
                      
                System.out.println(number2);
            
           else
            
                System.out.pringln(number);
           
         
         }
}

it tells me that there is an else with no if.. why is that?

Recheck you code. The braces are not complete.

it tells me that there is an else with no if.. why is that?

Always use braces ({}) with your if,else, while, for ... statements as mentioned by the Sun Java coding conventions and you will be able to spot your error.

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