what i am trying to do here. is to let the user type a hexadecimal number
http://en.wikipedia.org/wiki/Hexadecimal
and then display it.
import java.io.*;
class Ex23
{
public static void main(String[] args)
{
Console console=System.console();
System.out.println("please type a hexadecimal number");
String input;
input=console.readLine();
int number;
int number=Integer.parseInt(input);
int count=0;
char c= input.charAt(0);
c= console.readline(input);
String abc= "abcdef";
if(c!=number)
while(c==abc.charAt(count))
{
number2=count+9;
count++;}
System.out.println(number2);
else
System.out.pringln(number);
}
}
it tells me that there is an else with no if.. why is that?