How to make array's element contain only one digit of number?

[Jeffrey0209]

This is the code wrote so far..
I'm new to Cprograming. please help thank you!

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

//Compute f(n)=n!, for 0<=n<=100
void f(int n){

// Adjust the array a so that each array element contains a single
// digit without altering the number represented by the array a.
// Be sure to maintain m – the number of digits stored in the array a.

    short a[158];
    int m = 0;
    a[m] = 1;  // 0! = 1; a has m+1 digits
    int i, j, k ;

    for (k=2;k<=n;k++) {    // compute k!
        for (i=0;i<=m;i++)
        a[i]*=k;
        if(a[i]>=10) m++;
    }
    for(j=0;j=m;j++)
        printf("%d! = %d",n,a[j]);
        printf("%d",m);
}
/*
bool palindrome(unsigned n){

    char d[10];

}
*/
void main(){

    int i, j;

    for(;;){
        printf ("Enter your choice ( 1-factorial, 2-palindrome, ^z-exit ) :");
        scanf ("%d",&i);
            if (i==1){
                printf ("Enter an interger >=0 and <=100 :");
                scanf("%d",&j);
                f(j);

            }
           /*Part B: Palindrome
        
            else if(i==2){

            }*/
            else if (i==NULL){
                break;
            }
            else printf("Input 1 or 2. Try again.");

    }

    getch();
}

[abhimanipal]

Can you provide some sample inputs and outputs ?
I am unable to understand what does palindrome and factorials have to do with the problem that you have posted

[Jeffrey0209]

well let forget about the palindrome.
so for example
input =10
output= 10!=362880
10!=3628800.
what i want to know is how to make
a[0]=3 a[1]=6 a[2]=2 a[3]=8 a[4]=8 a[5]=0 a[6]=0

my friend tell me to use
if(a>=10) a[i+1]++; a=a%10;
but i still haven figure it out yet

[Jeffrey0209]

my privious code but still have some bug

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

//Compute f(n)=n!, for 0<=n<=100
void f(int n){

// Adjust the array a so that each array element contains a single
// digit without altering the number represented by the array a.
// Be sure to maintain m ¡V the number of digits stored in the array a.

    short a[158];
    int m = 0;
    a[m] = 1;  // 0! = 1; a has m+1 digits
    int i, j, k ;

    for (k=2;k<=n;k++) {    // compute k!
        for (i=0;i<=m;i++)
        a[i]*=k;
        while(a[m]>=10){
            a[i+1]++; a[i]=a[i]%10;
        }
    }
    for(j=0;j<=m;j++)
        printf("%d! = %d \n",n,a[j]);
        printf("%d! has %d \n",n,m);
}
/*
bool palindrome(unsigned n){

    char d[10];

}
*/
void main(){

    int i, j;

    for(;;){
        printf ("Enter your choice ( 1-factorial, 2-palindrome, ^z-exit ) :");
        scanf ("%d",&i);
            if (i==1){
                printf ("Enter an interger >=0 and <=100 :");
                scanf("%d",&j);
                f(j);

            }
           /*Part B: Palindrome

            else if(i==2){

            }*/
            else if (i==NULL){
                break;
            }
            else printf("Input 1 or 2. Try again.");

    }

    getch();
}

[Jeffrey0209]

Can you provide some sample inputs and outputs ?
I am unable to understand what does palindrome and factorials have to do with the problem that you have posted

my privious code but still have some bug
it only go up to 7! 8! then something is wrong
i guess that my m doesn't go up..

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

//Compute f(n)=n!, for 0<=n<=100
void f(int n){

// Adjust the array a so that each array element contains a single
// digit without altering the number represented by the array a.
// Be sure to maintain m ¡V the number of digits stored in the array a.

    short a[158];
    int m = 0;
    a[m] = 1;  // 0! = 1; a has m+1 digits
    int i, j, k ;

    for (k=2;k<=n;k++) {    // compute k!
        for (i=0;i<=m;i++)
        a[i]*=k;
        while (a[i]>=10){
            a[i+1]++; a[i]=a[i]%10;
        }
    }
    for(j=0;j<=m;j++)
        printf("%d! = %d \n",n,a[j]);
        printf("%d! has %d digits \n",n,m++);
}
/*
bool palindrome(unsigned n){

    char d[10];

}
*/
void main(){

    int i, j;

    for(;;){
        printf ("Enter your choice ( 1-factorial, 2-palindrome, ^z-exit ) :");
        scanf ("%d",&i);
            if (i==1){
                printf ("Enter an interger >=0 and <=100 :");
                scanf("%d",&j);
                f(j);

            }
           /*Part B: Palindrome

            else if(i==2){

            }*/
            else if (i==NULL){
                break;
            }
            else printf("Input 1 or 2. Try again.");

    }

    getch();
}