Member Avatar for hisan

Hi,
I want to know how to read the binary file from 10th byte to 90th byte in a file size of 100 bytes and need to write the read data into new binary file.
please help me in doing this.

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  • Latest Post Latest Post by hisan
Member Avatar for TrustyTony 
with open('binfile.dat', 'rb') as bf:
      bf.seek(10)
      open('out.dat', 'wb').write(bf.read(80))

Something like this. This is untested as I am not with computer now. Maybe you must seek(9) and/or read(81).

Edited by TrustyTony because: n/a
Member Avatar for woooee

You should be able to read the 100 bytes, split and write. The following code uses 25 bytes and splits from 10 through 20 (11 bytes) for simplicity.

alpha = "abcdefghijklmnopqrstuvwxy"
print alpha
print alpha[9:20]
Edited by woooee because: n/a
Member Avatar for hisan

The first solution really worked for me.. thanks

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