Member Avatar for camelCase

Hello DaniWebbers,

How would I go about taking user input into a string? It is not allowing me to do:

#include <iostream>
#include <string>
using namespace std;

int main() {

string users_name; // Reserved for the users name (input)
cout << "Enter your name: ";
cin >> users_name; // Compilation error 'No operator matches these operands'? 

getchar();
return 0;
}

I can't use "cin" nor "cin.getline()", not even "getline(cin,users_name)"...How do I get input form the user then put it into a string?

Thanks,
-camelCase

  • 4 Contributors
  • 5 Replies
  • 316 Views
  • 8 Hours Discussion Span
  • Latest Post Latest Post by Stefano Mtangoo

Dani AI

Generated

The snippet in the first post is valid C++ and compiles cleanly with standard C++ compilers. The error message reported ("No operator matches these operands") is most commonly caused by the source being compiled as C (wrong file extension or wrong compiler invocation) or by project/compiler settings that aren't using a C++ compiler. and are correct that the code builds fine under typical C++ toolchains; 's suggestion to try a different toolchain can help only if the current build is misconfigured.

Quick checklist to eliminate the usual causes:

  • Confirm the file uses a .cpp extension and is compiled with a C++ compiler (g++, clang++ or MSVC cl), not plain gcc.
  • In an IDE, ensure the project/language is set to C++ rather than C.
  • Keep #include <string> (already present) and either using namespace std; or use std:: prefixes.
  • Prefer std::cin.get() over C getchar() in C++ (or include <cstdio> if using getchar).
  • Check for accidental macros or a stray operator>> overload in the codebase that could shadow the standard overload.

Reading a full line (name with spaces) is best done with std::getline. Example:

#include <iostream>
#include <string>
#include <limits>

int main() {
    std::string name;
    std::cout << "Enter your name: ";
    std::getline(std::cin, name); // reads the whole line, spaces allowed
    std::cout << "Your name is: " << name << '\n';
    return 0;
}

When mixing formatted extraction (operator>>) with getline, consume the leftover newline first, for example with std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); or use std::getline(std::cin >> std::ws, name);.

Final note: replacement of getchar() with std::cin.get() (as suggested) is a safe, portable C++ choice, and remember that Qt is a GUI toolkit, not a compiler (as pointed out).

Recommended Answers

All 5 Replies

Member Avatar for Ancient Dragon

what compiler are you using? Your program compiles without error on vc++ 2010 express.

replace getchar() with cin.get()

Edited by Ancient Dragon because: n/a
Member Avatar for XMasterrrr

just change the compiler to VS 2010 or QT 4.

Member Avatar for Stefano Mtangoo

just change the compiler to VS 2010 or QT 4.

QT is not compiler but GUI toolkit. may be you meant MinGW that comes with QT's IDE

Member Avatar for XMasterrrr

yea i know that's sir thank's too much but i think it can develop the normal source code on it

any way VS 2010 is the best solution for it

Member Avatar for Stefano Mtangoo

what compiler are you using? Your program compiles without error on vc++ 2010 express.

replace getchar() with cin.get()

Following the AD and the GCC works fine!

#include <iostream>
#include <string>
using namespace std;

int main() {

string users_name; // Reserved for the users name (input)
cout << "Enter your name: ";
cin >> users_name; // Compilation error 'No operator matches these operands'? 
cout << "Your name is: "<<users_name<<endl;
cin.get();
return 0;
}
Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.