Could anyone instruct me about the Python code for magic square 3*3, I got some instructions but still made no dent in program. Could anybody send me the code?
O(∩_∩)O Thanks!
here's the instrctions:
magic3
# In recreational mathematics, a magic square of order n
# is an arrangement of n^2 numbers, usually distinct
# integers, in a square, such that n numbers in all rows,
# all columns, and both diagonals sum to the same constant
# (this constant is the magic number).
# A normal magic square contains the integers from 1 to n^2.
# (From Wikipedia, the free encyclopedia.)
# Implement the function to find the arrangement of numbers
# for n=3. The returned arrangement must be a TUPLE of numbers,
# where the first 3 elements are for the first row; the
# second 3 for the second row, and the last 3 for the last row.
# For example, (1,2,3,4,5,6,7,8,9) corresponds to
# the following square:
# 1 2 3
# 4 5 6
# 7 8 9
# Hint: the magic number is always: n*(1+n*n)//2
# Hint: use itertools.permutations for brute force.
# Note: answer is not all, but how your code
# comes up with the answer.
O(∩_∩)O~
