I have a list of numbers in a 2d array. I need a random number without repeating.
The number zero cannot be shuffle.
int **map;
int * list;
void randomize(){
for ( int x=0;x<Width;x++)
{
for( int y = 0; y < Height; y++)
{
map[x][y]=list[x*y];
//add code
}
This is a c++ forum.
Still, the logic can be applied in C++.
I am trying to copy the map. It can only copy part of the map.
void randomize(int Width,int Height){
list = new int[Width*Height];
for ( int x=0;x<Width;x++)
{
for( int y = 0; y < Height; y++)
{
list[x*y]=map[x][y];
cout << map[x][y];
}
cout<<"\n";
}
}
The number zero cannot be shuffle.
Can you clarify what you mean by that?
It's not perfectly random by any stretch, but the easiest would be to choose a row and choose a column, check if that element's already in the list, if not add it, if so, choose a new row and column. I understand what you are trying to do, but I don't think it's the best approach.
Maybe what you're looking for is:
int* list = new int[Width][Height];Maybe what you're looking for is:
int* list = new int[Width][Height];
Did you try that in the compiler? It doesn't work. For a dynamic nthDimensional array you have to build it up.
[rows,columns]
int ** my2Darr = new int*[rows];
for (int i = 0;i<rows;i++)
my2Darr[i] = new int[columns]; //for each element of the row array, make a column arrayDid you try that in the compiler? It doesn't work. For a dynamic nthDimensional array you have to build it up.
[rows,columns]
int ** my2Darr = new int*[rows]; for (int i = 0;i<rows;i++) my2Darr[i] = new int[columns]; //for each element of the row array, make a column array
Now I know. Thank you.
I want to make a map with random numbers from the map. First, copy the map. Then paste it in the list. Now I need to shuffle those numbers.I don`t want to shuffle the number zero. Can you give me a hint?
void randomize(int Width,int Height){
list = new int*[Width];
for ( int x=0;x<Width;x++)
{
list[x] = new int[Height];
for( int y = 0; y < Height; y++)
{
list[x][y]=map[x][y];
cout << map[x][y];
}
cout<<"\n";
}
}Choose an x from the range of x, chose a y from the range of y, choose x1 from the range of x, choose y1 from the range of ys.
If list[x][y] or list[x1][y1] is 0, neither is swapped and a new set of x,y,x1,y1 is chosen.
Else, swap list[x][y] and list[x1][y1] and pick a new set of x,y,x1,y1
It's not as random as can be, but it should suffice for your assignment.
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