Member Avatar for Tweekler

Hey, so I need to calculate and display the mode (most frequently occuring number) from a vector of ints. I already have the vector, and it can have any number of elements in it. So now i need to figure out a way to loop through my vector to figure out the number that occurs most. I also need a message that says "No Mode" if there is an equal number of every number.

This is what I have so far but it doesn't work very well. Could any1 help me out? Vector is called "v"

double previous = 0;
	double current = 0;
	double mode = 0;
	for (int i = 0; i < v.size(); i++)
	{
		for (int j = 0; j < v.size(); j++)
		{
		if (v[j] == v[i])	
			current++;
		}
		if (current > previous) {
			mode = v[i];
			previous = current;
			current = 0;
		}
	}
		cout << "Mode = " << mode << endl;
  • 3 Contributors
  • 3 Replies
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  • 7 Hours Discussion Span
  • Latest Post Latest Post by mrnutty
Member Avatar for m4ster_r0shi

You are very close. You should set current to zero every time i changes, not just when it's big enough to become the current mode count.

EDIT: You were closer than I initially thought...

Edited by m4ster_r0shi because: n/a
Member Avatar for Tweekler

You are very close. You just need to fix two things.

(1) You should set current to zero every time i changes, not just when it's big enough to become the current mode count.
(2) It's not useful to compare the current count with the previous one. It would be better to compare it with the current mode count.

Wow thanks alot, that did the trick.

Member Avatar for mrnutty

You might consider sorting then evaluating it.

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