Member Avatar for dyingatmidnight

I swear I used to know how to do this ... so I have this array:

BYTE bcdData[6];

and a function that returns it:

BYTE * BCD::GetBcdData()
{
	return bcdData;
}

and I have this other array in another class:

BYTE tpIdByte[2];

And what I am trying to is take the values from bcdData array and place them in tpIDByte array. And I am running into a total blank on how to do it...

Thanks for the help.

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  • Latest Post Latest Post by ChaseRLewis
Member Avatar for mrnutty

You are trying to fit 6 bytes into 2, in general it's not possible, unless the data in bcd are very trivial or you can compress it. What kind of data does bcd hold? It might be possible if the data in bcd are small enough that you can use some compression techniques.

Member Avatar for ChaseRLewis

few ways

you can do something like

BCD foo;
tpldByte[0] = foo.getBcdData()[1];

where the arrays start at zero so 1 is the second value in the bcdData array and 0 is the first value in the tpldByte.
So if I wanted the last in tpldByte to equal the last byte of bcdData

tpldByte[1] = foo.getBcdData()[5];

you can also use memcpy for larger assignemtnts.

Edited by ChaseRLewis because: n/a
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