Member Avatar for owenransen

As far as normal ascii is concerned can I compare a wchar_t with a char type to see if they are equal?

I think, but do not know, that the most common ASCII chars have the same integer value in char and wchar_t. Is that true? Do I need to be careful?

The application I'm writing will also compare punctuation like , . : ; \t \n

Summarising, in UNICODE c++ when is this valid:

wchar_t wcA = ...
char chB = ...
if (wcA == chB) {
    ...
}
  • 5 Contributors
  • 5 Replies
  • 3K Views
  • 1 Day Discussion Span
  • Latest Post Latest Post by owenransen
Member Avatar for Caligulaminus

As long as you stay with ASCII I see no problem.

Member Avatar for caut_baia

I think that in the conditional expression the 8 bits variable gets promoted to a 16 bits wchar_t.

Edited by caut_baia because: n/a
Member Avatar for tajendra

I agree with caligulaminus, that with ASCII it will not give problem. Since ASCII need 1 byte for its representation. But if you talk about UNICODE content, then its not advisable to do so. Because UNICODE may use multiple bytes for character representation.

Member Avatar for vijayan121

> Do I need to be careful?

If you decide to be careful, the code would be something like:

wchar_t wc = L'A' ;
    char c = 'A' ;
    const auto& ctype = std::use_facet< std::ctype<wchar_t> >( std::locale() ) ;
    if( ctype.widen(c) == wc ) { /* whatever */ }
Member Avatar for owenransen

Thanks all. As long as my char code is less than 128 I think I'll be fine.

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.