Is there a way in C++ to deal with this? (a way to force that a boolean is strictly a boolean and cannot be converted to another numerical type?)
line 42: Error: Overloading ambiguity between "MultiLog::writeLog(const long&)" and "MultiLog::writeLog(const bool&)"
you might have some other problem. This works ok for me
#include <iostream>
using namespace std;
void foo(const long& l)
{
cout << l << endl;
}
void foo(const bool& l)
{
cout << l << endl;
}
int main(int argc, char* argv[])
{
bool b = true;
foo(b);
return 0;
}What about if you pass a long to the function in main?
What about if you pass a long to the function in main?
no problem with that either. why don't you post your program (zip it up first if its pretty long)
I figured it out. When I pass an int, it can't decide whether to use the bool or the long. I think I just need to create an int version of the function as well...
or you can cast your int to long or bool...
or use a template?? I'm not very good at them, so don't ask me how.
or use a template?? I'm not very good at them, so don't ask me how.
I could use a template or do the cast, the problem is that I want to do special processing based on the type (ie if it's a bool, then print it out as 'TRUE' or 'FALSE', etc. By adding the function for int, it worked out fine.
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