Can`t find the mistake!

[DoubleZ]

Hello guys!
Basically I have this basic homework, the program must check if the digit sum of one of the 3 inputted integers is equal to the difference of 2 others. So if A = 56, B = 33 and C = 22, the program should output 56, cause 5+6 = 33 - 22. I think I have the code but I can`t find whats wrong, it always says that such number is not found even tho it should be. Thanks!

#include <iostream>
using namespace std;
int main()
{
    int a, b, c, suma = 0, sumb = 0, sumc = 0, diga = 0, digb = 0, digc = 0, ok;
    do
    {
        do
        {
            cout << "Input 3 integers" << endl;
            cin >> a >> b >> c;
            if (a <= 0 || b <= 0 || c <= 0)
            {
                cout << "You entered invalid data" << endl;
            }
        } while (a <= 0 || b <= 0 || c <= 0);
        do
        {
            diga = a % 10;
            suma+= diga;
            a = a / 10;
        } while (a > 0);
        do
        {
            digb = b % 10;
            sumb+= digb;
            b = b / 10;
        } while (b > 0);
        do
        {
            digc = c % 10;
            sumc+= digc;
            c = c / 10;
        } while (c > 0);
        if (suma == b-c || suma == c-b)
        {
            cout << a << endl;
        }
        else if (sumb == a-c || sumb == c-a)
        {
            cout << b << endl;
        }
        else if (sumc == a-b || sumc == b-a)
        {
            cout << c << endl;
        }
        else
        {
            cout << "Does not exist" << endl;
        }
        cout << "Continue (1) or end (0)?" << endl;
        cin >> ok;
    } while (ok == 1);
    return 0;
}

[vidit_X]

You are changing the value of variables(a, b and c) while computing the sum of their digits.

a=a/10;

Then you compare them with the sum.

[DoubleZ]

Any possible solutions? :(

[Taywin]

You just need to have another set of variables to keep the division. Do not reassign your variable a, b, or c at all.

// i.e.
int tmpA = a;
do {
  diga = tmpA % 10;
  suma+= diga;
  tmpA = tmpA / 10;
} while (tmpA > 0);

Also, this assumes that the rest of your algorithm is correct...

[DoubleZ]

Oh, right! Thank you!

[DoubleZ]

Hello, I recently came across a situation when 2 numbers are ok, for instance 9 14 and 23, 2+3 = 14-9 and also 9 = 23-14, so it should print out 23 and 9 but it doesn`t. Also if I change `else if`s to `if`s it prints out all the right numbers but always prints out `Does not exist` as well, is there a way to do this without huge repetition of code, which is the only way I know atm.

[Fbody]

Do you know how to use functions? You could replace your evaluation with a function. Then, when you need an evaluation done, all you have to do is call the function. This eliminates the repetition by allowing you to re-use one piece of code.

Perhaps something like this:

bool evalDigitSum(int valToSum, int compare1, int compare2) {
  //calc digit sum for "valToSum" parameter
  //calculate difference between "compare#" parameters
  //compare digit sum with calculated difference
  //return appropriate bool value
}

[DoubleZ]

Nope, I do not know how to use functions yet, so I guess I`ll have to repeat the code then.