Member Avatar for terey 
#include "stdafx.h"
#include <iostream>



using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
	char ch;
	
	do{
		cout<<"press Q or q to quit,press any key to continue  :  ";
		cin.get(ch);
		cin.ignore();
		
		if(ch!='Q'&&ch!='q')
			cout<<" you want to continue?\n";

		else
			cout<<"you press q to quit ";
		
		
	}while(ch!='Q'&&ch!='q');
	;

	system("pause>NULL");
	return 0;
}

my prof said that whenever how many the letter i input the output must be just one..
output
press any key to continue : ma.teresa l. sagun
you want to continue?
press any key to continue :
you want to continue?
press any key to continue :
you want to continue?
press any key to continue :
you want to continue?
press any key to continue :
you want to continue?
press any key to continue :
you want to continue?
press any key to continue :

it appears like this..will someone help me..

Edited by Narue because: added code tags
  • 6 Contributors
  • 5 Replies
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  • Latest Post Latest Post by gyme20
Member Avatar for dospy

you must provide CLEAR details if you want people to help you, what exactly is suppose your code to do?

commented: . +7
Member Avatar for Taywin

Looks like the ch.get(ch) takes each of your input character in and execute them one by one. As a result, each character is being checked in the loop.

Member Avatar for vidit_X

Flush the input stream after input...

while (cin.get (temp) && temp != '\n');
Member Avatar for maytinhxachtay

fflush(stdin) will help you!
from: <snipped link>

Edited by Narue because: Removed link
Member Avatar for gyme20

post your question on <link removed>, computer experts will answer your question quickly.

hi, guys
have you solved your problem?

Edited by Narue because: Edited spammy link from quote
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