if() statement glitches

[YourGamerMom]

I used a multi dimensional array:

int grid[3][3];

then I assigned all the variables in the array to the number 2 like this:

grid[0][0] = 2;
	grid[0][1] = 2;
	grid[0][2] = 2;
	grid[1][0] = 2;
	grid[1][1] = 2;
	grid[1][2] = 2;
	grid[2][0] = 2;
	grid[2][1] = 2;
	grid[2][2] = 2;

not the most efficient way, I know, but that is what I did.
Then I tried to print letters corresponding to their numbers:

if(grid[0][0] = 2){printf("\n_");}
	if(grid[0][0] = 1){printf("\nX");}
	if(grid[0][0] = 0){printf("\nO");}
	if(grid[0][1] = 2){printf("_");}
	if(grid[0][1] = 1){printf("X");}
	if(grid[0][1] = 0){printf("O");}
	if(grid[0][2] = 2){printf("_");}
	if(grid[0][2] = 1){printf("X");}
	if(grid[0][2] = 0){printf("O");}
	if(grid[1][0] = 2){printf("\n_");}
	if(grid[1][0] = 1){printf("\nX");}
	if(grid[1][0] = 0){printf("\nO");}
	if(grid[1][1] = 21){printf("X");}
	if(grid[1][1] = 0){printf("O");}
	if(grid[1][2] = 2){printf("_");}
	if(grid[1][2] = 1){printf("X");}
	if(grid[1][2] = 0){printf("O");}
	if(grid[2][0] = 2){printf("\n_");}
	if(grid[2][0] = 1){printf("\nX");}
	if(grid[2][0] = 0){printf("\nO");}
	if(grid[2][1] = 2){printf("_");}
	if(grid[2][1] = 1){printf("X");}
	if(grid[2][1] = 0){printf("O");}
	if(grid[2][2] = 2){printf("_");}
	if(grid[2][2] = 1){printf("X");}
	if(grid[2][2] = 0){printf("O");}

but when I run it it gives me this:

_
X_X_X
_
X_X_X
_
X_X_X

what is wrong and how do I fix it? Thanks.

[thines01]

use double-equals in the comparison.
==

if(grid[0][0] == 2){printf("\n_");}

[skaa]

Comparison must use double equals sign like:

if(grid[0][0][B]==[/B]2){printf("\n_");}
if(grid[0][0][B]==[/B]1){printf("\nX");}

[YourGamerMom]

use double-equals in the comparison.
==

if(grid[0][0] == 2){printf("\n_");}

thanks, it works now!