so to create a thread all i need is to call this function? and the codes in the "void *(*start_routine)" function is a thread?

int pthread_create(pthread_t *thread, const pthread_attr_t *attr,
    void *(*start_routine)(void*), void *arg);

start_routine is the entrance point of the thread create with pthread_create.

Yeah, that's pretty much it. Try this for instance:

#include <pthread.h>
#include <iostream>

void* f(void*) {
  for(int i = 0; i < 1000; ++i) {
    std::cout << "Print from the Thread!" << std::endl;
    usleep(1000);
  };
  return NULL;
};

int main() {
  pthread_t threadID;
  pthread_create(&threadID, NULL, f, NULL);
  for(int i = 0; i < 1000; ++i) {
    std::cout << "Print from the Main Function!" << std::endl;
    usleep(1000);
  };
  pthread_join(threadID, NULL);
  return 0;
};

Compile with:

$ g++ pthread_example.cpp -o pthread_example -lpthread
commented: cool! i love your example! +3
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