How to sort emerged Arrays using compareTo method

Question

huphane -3 Newbie Poster

12 Years Ago

public class Exercise {

/**
 * @param args the command line arguments
 */

public static void main(String[] args) {


     String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};
    String B[] = {"Madona","Diddy","Joe","Alice"};


             for(int j = 0; j < A.length; j++) {
            for(int s = j +1; s < B.length; s++)
      for(int i = 0 ; i < B.length; i++) { 
      if(A[j].compareToIgnoreCase(B[i]) < 0) { 

      } 
       } 

       List<String> list = new ArrayList(Arrays.asList(A));
        list.addAll(Arrays.asList(B));
       Object[] C = list.toArray();


       System.out.println(Arrays.toString(C));




    }
        }
            }

And the out put was like this:

run:
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
[Joseph, Ariana, Xena, Rene, Peter, Diana, Rihanna, Madona, Diddy, Joe, Alice]
BUILD SUCCESSFUL (total time: 6 seconds)

java

Edited 12 Years Ago by Ezzaral because: code formatting

3 Contributors
26 Replies
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3 Weeks Discussion Span
Latest Post 12 Years Ago Latest Post by NormR1

NormR1 563 Posting Sage

12 Years Ago

What are the results when you execute the code?

Post the full text of the error messages here.

Edited 12 Years Ago by NormR1

NormR1 563 Posting Sage

12 Years Ago

What does the print out show? The 7 lines you printed all look the same. Why were 7 lines printed?
Can you print the array before sorting and again after sorting it to show what the sort code has done?

NormR1 563 Posting Sage

12 Years Ago

Add this after you sort the C array to see its contents:
System.out.println("C after sort=" + Arrays.toString(C));

I can not read and understand your code because it is very poorly formatted. The }s shoud be vertically beneath the statement with its paired {
Your }s are not in the correct columns

Edited 12 Years Ago by NormR1

TrustyTony 888 pyMod

12 Years Ago

I would fix your code tags but it has no value as your code formatting indention does not make any kind of sense. See Formatting help from link in right top corner of the editor box. Basically you should highlight your code and push TAB to indent it. But first you have to have some indention worth showing.

TrustyTony 888 pyMod

12 Years Ago

Not being Java programmer, but knowing the general principles, I would expect formatting similar to this from your code:

public class Exercise {
    public static void main(String[] args) {
           String A[] = {"Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};
           for(int j = 0; j < A.length; j++) {
                   for(int i = j +1; i < A.length; i++) {
                           if(A[i].compareToIgnoreCase(A[j]) < 0) {
                                String K = A[j];
                                A[j] = A[i];
                                A[i] = K;
                           }
                   }
                   System.out.println(A[j]);
           }
    }
}

Can you see any change in readability?

Edited 12 Years Ago by TrustyTony

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huphane -3 Newbie Poster · Answer 1 · 2012-04-06T17:46:26+00:00

I have rearranged question and add some more information?

huphane -3 Newbie Poster · Answer 2 · 2012-04-06T19:23:21+00:00

First i merged the two arrays:

public static void main(String[] args) {


         String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};
        String B[] = {"Madona","Diddy","Joe","Alice"};


        List<String> list = new ArrayList(Arrays.asList(A));
      list.addAll(Arrays.asList(B));
      Object[] C = list.toArray();


      System.out.println(Arrays.toString(C));




    }
}

How to be connected with these two functions:

      for(int j = 0; j < C.length; j++) { 

   for(int i = j + 1; i < C.length; i++)  {

      if(C[i].compareToIgnoreCase(C[j]) < 0)  { 

      String K = C[j]; 

        C[j] = A[i]; 

      C[i] = K; 

      } 

      } 

  System.out.println(C[j]);


  } 
 }

huphane -3 Newbie Poster · Answer 3 · 2012-04-06T19:49:49+00:00

Do you mean like this:

  public class Opdracht1 {


   public static void main(String[] args) {


     String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};

    String B[] = {"Madona","Diddy","Joe","Alice"};



       ** List<String> list = new ArrayList(Arrays.asList(A));

      list.addAll(Arrays.asList(B));

      Object[] C = list.toArray();

**

                        System.out.println("C after sort=" + Arrays.toString(C));


                       **for(int j = 0; j < C.length; j++) { 


                       for(int i = j + 1; i < C.length; i++) { 


                 if(C[i].compareToIgnoreCase(C[j]) < 0) { 


                    String K = C[j];


                     C[j] = A[i]; 


              C[i] = K; **


           } 


             } 


                  System.out.println(C[j]);




     }
       }
                }

NormR1 563 Posting Sage Team Colleague · Answer 4 · 2012-04-06T20:14:38+00:00

Is the call to println on line 14 before or after the code that does the sorting?

You should show the C array both before and after you sort it.

huphane -3 Newbie Poster · Answer 5 · 2012-04-06T20:18:50+00:00

huphane -3 Newbie Poster

12 Years Ago

I made some changes but is it enough.

NormR1 563 Posting Sage Team Colleague · Answer 6 · 2012-04-06T20:24:37+00:00

No. For example the last } in the code should be in column 1. The } on line 34 is to the right of the } on line 33. It should be to the left.
Your extra blank lines also make the code hard to read.

You did not have the code print out the array both before the sort and after the sort. The comment with where you do print the array looks wrong.

huphane -3 Newbie Poster · Answer 7 · 2012-04-06T20:36:49+00:00

Let me start the whole story over again. I have sorted one array using compareTo method:

               public class Exercise {

               public static void main(String[] args) {


     String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};


                    for(int j = 0; j < A.length; j++) {
                        for(int i = j +1; i < A.length; i++) {
            if(A[i].compareToIgnoreCase(A[j]) < 0) { 

            String K = A[j]; 
            A[j] = A[i]; 
            A[i] = K; 
            } 
            } 
            System.out.println(A[j]);


            } 
            } 
            }

This was the original exercise and i have got it working, but i asked myself "How about

if you got two arrays how you gonna do it? So if you add an other array like this one:

  String B[] = {"Madona","Diddy","Joe","Alice"};

How you get the job done?

NormR1 563 Posting Sage Team Colleague · Answer 8 · 2012-04-06T20:43:21+00:00

A little better. However there should NOT be }s one below the other like lines 24, 25 and 26.

Lines 16,17,18 should be indented to show they are inside of the if statement.

After you merge the two arrays, you have one array. You have the code to sort that one array.

huphane -3 Newbie Poster · Answer 9 · 2012-04-06T20:57:55+00:00

If you remove one of those )s you get a compile error, i have tried it.

NormR1 563 Posting Sage Team Colleague · Answer 10 · 2012-04-06T21:09:22+00:00

I'm talking about what columns they should be in, their alignment and positions. The compiler will tell you if there are too many or too few. The comiler does not care what columns they are in. You could put all the code on one line and get it to compile.

huphane -3 Newbie Poster · Answer 11 · 2012-04-06T22:00:55+00:00

Thanks i can see the chages: Can anybody connect those two methods?

    package ExeCise1;

   import java.util.ArrayList;
   import java.util.Arrays;
   import java.util.List;




  public static void main(String[] args) {

    String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};

           String B[] = {"Madona","Diddy","Joe","Alice"};

              List<String> list = new ArrayList(Arrays.asList(A));

                 list.addAll(Arrays.asList(B));

                     Object [] C = list.toArray();

                        System.out.println(Arrays.toString(C));


                        Here starts the trick. How can you connect those two methods?



                   **  for(int j = 0; j < C.length; j++) {

                         for(int i = j +1; i < C.length; i++) {

                           if(C[i].compareToIgnoreCase(C[j]) < 0) {

                                  String K = C[j]; 

                                      C[j] = C[i]; 

                                           C[i] = K; 


                                        }

                                  }

                                 System.out.println(A[j]);


                          }

                      }

               }

    **

NormR1 563 Posting Sage Team Colleague · Answer 12 · 2012-04-06T23:39:51+00:00

Your formatting is still wrong. DO NOT indent every line of code. Indent code within {}s.

Look at how the previous post by pyTony formatted code.

connect those two methods?

There is only one method named main in your code.
Can you explain what you mean?

Have you tried compiling the code you posted?

Please post here the compiler error messages you get.

huphane -3 Newbie Poster · Answer 13 · 2012-04-07T22:01:31+00:00

public class Exercise {

        /**
       * @param args the command line arguments
       */

        public static void main(String[] args)       {


     String A[] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};

          String B[] = {"Madona","Diddy","Joe","Alice"};




           List<String> list = new ArrayList(Arrays.asList(A));

                  list.addAll(Arrays.asList(B));

                          Object[] C = list.toArray();


                                  System.out.println(Arrays.toString(C));




                }
        }







            Can anyone help me sorting Array C{} using compareTo method Like this:







                    for(int j = 0; j < C.length; j++)    { 

                            for(int i = j + 1; i < C.length; i++) {

                                    if(C[i].compareToIgnoreCase(C[j]) < 0) { 

                                            String K = C[j]; 

                                                C[j] = C[i]; 

                                                    C[i] = K; 

                            } 

                      } 

                                System.out.println(C[j]);



            } 

 }

huphane -3 Newbie Poster · Answer 14 · 2012-04-07T23:26:28+00:00

Even I tried this way:

         public static void main(String[] args) {


     String a [] = { "Joseph","Ariana","Xena","Rene","Peter","Diana","Rihanna"};

      String b  [] = {"Madona","Diddy","Joe","Alice"};

    ArrayList list = new ArrayList() ;

    list.add(a);

    list.add(b);

  Collections.sort( list, new Comparator()
                                                                       {

        @Override
                 public int compare( Object a, Object b )

                                                                               {

                    return( (String)a ).compareToIgnoreCase( (String) b );

                       }

                 } 




                 It doesnot work

NormR1 563 Posting Sage Team Colleague · Answer 15 · 2012-04-07T23:59:52+00:00

Does it compile? If not post the error messages.

Where do you print out the before list and the after list?

Why so many blank lines? That makes the code very hard to read.

You are continually ignoring our requests to format the code that you post so that is is readable.
You also ignore our coding suggestions like printing the list before and after the sort.
Can you explain your actions?

Why should anyone try to help you if you continue to ignore what is recommended???

huphane -3 Newbie Poster · Answer 16 · 2012-04-08T10:17:14+00:00

/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package exercise1;

                import java.util.*; 


                /**
                 *
                 * @author joseph
                 */
                    public class exercise {

                    /**
                     * @param args the command line arguments
                     */

                    public static void main(String[] args) {


                         String a [] = { "Joseph","Ariana","Xena","Rene","Peter","Diana",
                "Rihanna"};
                        String b  [] = {"Madona","Diddy","Joe","Alice"};

                        ArrayList list = new ArrayList() ;
                        list.add(a);
                        list.add(b);

                      Collections.sort( list, new Comparator()
                                                                     {
                            @Override
                                     public int compare( Object a, Object b )
                                                                                    {
                                     return( (String)a ).compareToIgnoreCase( (String) b );

                             }


                });


                        the error compiler is here:




                                                        run:
                       Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.String; cannot be cast to java.lang.String
                                at opdracht1.Opdracht1$1.compare(Opdracht1.java:36)
                                at java.util.TimSort.countRunAndMakeAscending(TimSort.java:324)
                                at java.util.TimSort.sort(TimSort.java:189)
                                at java.util.TimSort.sort(TimSort.java:173)
                                at java.util.Arrays.sort(Arrays.java:659)
                                at java.util.Collections.sort(Collections.java:217)
                                at opdracht1.Opdracht1.main(Opdracht1.java:31)
                            Java Result: 1
                            BUILD SUCCESSFUL (total time: 1 second)

NormR1 563 Posting Sage Team Colleague · Answer 17 · 2012-04-08T11:45:17+00:00

[Ljava.lang.String; cannot be cast to java.lang.String

You have not posted the line with the error. What is on line 36?
The error says that you are tring to cast an object that is an array of String to a String.

If you would print out the contents of list before the sort you might see what was in list.

huphane -3 Newbie Poster · Answer 18 · 2012-04-08T13:45:46+00:00

Thanks, i'll try other ways and see how it responses.

huphane -3 Newbie Poster · Answer 19 · 2012-04-08T14:47:17+00:00

I got the solution. So if anybody else needs it, it is here:

                 /*
             * To change this template, choose Tools | Templates
             * and open the template in the editor.
             */
            package ExerCise;




            /**
             *
             * @author Huphane
             */
            public class Exrcise           {

                /**
                 * @param args the command line arguments
                 */

                public static void main(String[] args)     {

                    String[] A = { "Joseph","Ariana","Xena","Rene","Peter","Diana" };
                     String[] B = { "Madona","Diddy","Joe","Alice","Brian","Sara" };
                    String[]  C = new String[A.length + B.length];


                   System.arraycopy(A, 0,  C, 0, A.length);
                   System.arraycopy(B, 0,  C,  A.length, B.length);

                for (int i = 0; i < C.length; i++)  {
                    for(int j = i + 1 ; j <  C.length; j++) {
                        if( C[j].compareToIgnoreCase( C[i]) < 0)          {

                            String K =  C[j];
                            C[j] =  C[i];
                            C[i] = K ;
                            }

                    }
                  System.out.println(  C[i]);



              }    
          }
       }

huphane -3 Newbie Poster · Answer 20 · 2012-04-27T21:54:39+00:00

Hi Guys, I have solved my earlier question, but i am trying to do it in another way and i am stuck:
I need to compare two sorted string arrays to arranged in alphabetical order without sorting them but using compareTo method or overloading. just to get the whole list arranged. first comparing Ariana with Alice if Ariana > is than Alice print Alice, then comparing Ariana and Brian if Ariana < is than Briana print Brian and than comparing Brian and Diana so on.        

  package opdarcht1;

  public class Opdarcht1 {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    String[] A = { "Ariana","Diana","Joseph","Peter","Rene","Xena" };
    String[] B = { "Alice","Brian","Diddy","Joe","Madonna","Sara" };


                  for (int i = 0; i < A.length; i++)      {
                     for(int j = 0 ; j <  B.length; j++)      {
                         if( A[i] > B[j])                          {
                         System.outprintln(B[j]);
                         }
                         alse
                         System.out.println(A[i]);


                      }


              }


     }

NormR1 563 Posting Sage Team Colleague · Answer 21 · 2012-04-27T23:54:41+00:00

NormR1 563 Posting Sage

12 Years Ago

Post the output to show what the code does.

Edited 12 Years Ago by NormR1