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A program for

A
BC
DEF
GHIJ
KLMNO

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  • Latest Post Latest Post by deceptikon
Member Avatar for Ancient Dragon

Use two loops, one nested inside the other. The outermost loop counts rows (1-5) and the inner loop counts from 0 to the value of the outer loop.

Member Avatar for deceptikon

A program for

A
BC
DEF
GHIJ
KLMNO

That's kind of weird, but okay:

#include <iostream>

using namespace std;

int main()
{
    cout << "A\nBC\nDEF\nGHIJ\nKLMNO\n";
}

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