2-D Arrays and pointers

[anumash]

I understood that when you pass the name of the array as an argument to a function we are actually passing the base address of the array, which inturn gets collected by a pointer variable and thus s[i]=(s+i)=(i+s)=i[s]. The problem begins when we turn to 2-D arrays. When we want to access a column element i.e s[i][j] in pointer notation this becomes ((s+i)+j). What is the logic for this? I understood that in memory the arrays are all 1-D arrays and 2-D arrays are nothing but array of arrays i.e. the individual rows become arrays. Based upon this understanding can someone explain the logic of using ((s+i)+j) to access 2-D array elements?

[Moschops]

When we want to access a column element i.e s[i][j] in pointer notation this becomes ((s+i)+j)

Not quite. Multiply i by the size of the first array dimension.

s[i][j] = s[(i*original length of first dimension) + j]

[anumash]

http://www.cs.cmu.edu/~ab/15-123S09/lectures/Lecture%2006%20-%20%20Pointer%20to%20a%20pointer.pdf. This is where I read it.
sorry if i missed out the dereference operator in the first post. :)

[anumash]

Thanx alot @Moschops...I kinda figured out my mistake....In a 2-d array the compiler assigns ADDRESSES to every ROW in the array and hence we can access a 2-d array as ((s+i)+j).