#include <iostream>
#include <string>
using namespace std;
struct record {
string C0;
string C1;
string C2;
};
int main()
{
record param;
param.C0 = "heading1";
param.C1 = "heading2";
param.C2 = "heading3";
string key = "CO";
string data = param.C0;
cout << "DATA: " << data << endl;
return 1;
}Is it possible to replace 'C0' with the variable 'key'?
ie:
string data = param.??key??; // where key is interpolated to 'C0'.
No.
Like
#include <iostream>
#include <string>
using namespace std;
struct record {
string C[3];
};
int main()
{
record param;
param.C[0] = "heading1";
param.C[1] = "heading2";
param.C[2] = "heading3";
int key = 0;
string data = param.C[key];
cout << "DATA: " << data << endl;
return 0; // zero is success
}Or maybe
#include <iostream>
#include <string>
#include <map>
using namespace std;
int main()
{
map<string,string> param;
param["C0"] = "heading1";
param["C1"] = "heading2";
param["C2"] = "heading3";
string key = "C0";
string data = param[key];
cout << "DATA: " << data << endl;
return 0;
}Thanks...
Your first sample would not work for me because I canot array the actual 'key' names (bad example on my part).
Your second example, using <map>, will work. I had tried it earlier and could not get it to work in VC++. I got some 117 warnings..
This was fixed by adding...
#pragma warning(disable:4786)
see: http://www.daniweb.com/techtalkforums/showthread.php?t=31283&highlight=%26lt%3Bmap%26gt%3B
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