Hello.
mylist = [6, '/', 3, '+', 9, '+', 8, '+', 1, '/', 2]
How can i delete that list indexes?
I tried:
def clear(self, event):
global numbers
for i in numbers:
print i
del numbers[i]
But it didn't work:
File "./kivycal", line 83, in clear
del numbers[i]
TypeError: list indices must be integers, not str
What can i do for that?
Just currect it:
numbers = [6, '/', 3, '+', 9, '+', 8, '+', 1, '/', 2]
To empty the list, use
numbers[:] = []
Yes!! Thank you @Gribouillis.
mylist = [6, '/', 3, '+', 9, '+', 8, '+', 1, '/', 2]
print(mylist)
# replace mylist with an empty list
mylist = []
print(mylist) # --> []
mylist = [6, '/', 3, '+', 9, '+', 8, '+', 1, '/', 2]
# delete part of a list, keep the first 7 elements
del mylist[7:]
print(mylist) # --> [6, '/', 3, '+', 9, '+', 8]
mylist = [6, '/', 3, '+', 9, '+', 8, '+', 1, '/', 2]
# delete part of a list, keep the last 3 elements
del mylist[:-3]
print(mylist) # --> [1, '/', 2]
Thank you @vegaseat, was helpful too.
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