WAP to check student is first ,second or third .
If number is greater than equal to 60->>first
If number is greater than equal to 45->>second
If number is greater than equal to 33->>third
If other than that ->>fail
Kumarvarun0609 -3 Newbie Poster
Reverend Jim commented: Lazy AND rude. -3
rproffitt 2,693 https://5calls.org Moderator
What is WAP? As I deal with networks that would be Wireless Access Point so that's not right.
As to the rest, we ask you to show your work and explain where you are stuck.
Reverend Jim 5,179 Hi, I'm Jim, one of DaniWeb's moderators. Moderator Featured Poster
I'm assuming that because the OP was too lazy to try this on his own first, he was also too lazy to expand WAP to "Write A Program".
Santosh_23 -6 Newbie Poster
You can use python if-else block to solve this problem:
i = raw_input("Enter marks : ")
if i >= 60:
print("first")
elif i < 60 and i >= 45:
print("second")
elif i < 45 and i >= 33:
print("third")
else:
print("fail")
JamesCherrill 4,733 Most Valuable Poster Team Colleague Featured Poster
Why the redundant tests?
Line 4: we know that i<60 because of the if test in line 2, so that part of the test is redundant.
Ditto the <45 on line 6
hussainmujtaba -3 Newbie Poster
I assume that you are either a beginner or a non programmer. Here is how your problem can be solved.I have tried to modify the above answer to make it a more easy for you.
marks = int(input("Enter marks : "))
if marks >= 60:
print("first")
elif marks >= 45:
print("second")
elif marks >= 33:
print("third")
else:
print("fail")Also if you want to know how this code actually works, read this article Python from scratch
Be a part of the DaniWeb community
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.