I know you can get the present time this way:
import time
now = time.asctime(time.localtime())
print now # Mon Feb 19 10:41:32 2007
How can I make sure that 'now' does not fall on our lunchtime break, let's say 11:30AM to 12:45PM?
I know you can get the present time this way:
import time
now = time.asctime(time.localtime())
print now # Mon Feb 19 10:41:32 2007
How can I make sure that 'now' does not fall on our lunchtime break, let's say 11:30AM to 12:45PM?
Untested!
lunch_start = time.mktime(time.strptime("11:00-20.02.2007","%H:%M-%d.%m.%Y"))
lunch_end = time.mktime(time.strptime("12:30-20.02.2007", "%H:%M-%d.%m.%Y"))
now = time.mktime(time.localtime())
if lunch_start < now < lunch_end:
print "Hey, it's lunch time!!
I modified mawe's code so you don't have to worry about the date of the day:
# using just time and not date ...
import datetime
lunch_start = datetime.time(11, 30)
lunch_end = datetime.time(12, 45)
now = datetime.datetime.now().time()
# testing
print lunch_start # 11:30:00
print lunch_end # 12:45:00
print now # eg. 09:05:59.750000
# you can compare type 'datetime.time' directly
if lunch_start < now < lunch_end:
print "Hey, it's lunch time! Mahlzeit!!"
elif now < lunch_start:
print "Lunch is pretty soon!"
else:
print "Darn, missed lunch time!!"
Thanks mawe and uran, for your very useful information! I figured Python could do that easily!
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