Converting Decimal Value to Binary (MIPS)

[bastek]

Hi,

I have a simple code written in MIPS assembly that reads an integer from a user and displays it to the screen. The code is as follows:

main:
     la         $a0, in_msg
     li         $v0, 4
     syscall
 
     li         $v0, 5
     syscall
     move       $t0, $v0
 
     la         $a0, out_msg
     li         $v0, 4
     syscall

     move       $a0, $t0
     li         $v0, 1
     syscall
     
     li         $v0, 10
     syscall

.data
     in_msg:    .asciiz "Input: "
     out_msg:   .asciiz "\nOutput:\n-------\n"

How can I convert this decimal value to a binary?

Thank you in advance.

[RustyBEW]

I am currently trying to work on this. If anyone can help...it would be greatly appreciated.

[Duoas]

Post what you've got and what part of it is giving you trouble.

[RustyBEW]

Post what you've got and what part of it is giving you trouble.

I figured it out:

# Brent Wagner

.data
ask_str1: .asciiz "Enter a number PLEASE: "
result_str: .asciiz ""
.align 2

.text
.globl __start

__start:
# ask and store the first number
li $v0, 4
la $a0, ask_str1
syscall
li $v0, 5
syscall
move $a0, $v0

jal print_bin

# New Line
li $v0, 11
li $a0, 10
syscall

j __start

print_bin:

add $t0, $zero, $a0 # put our input ($a0) into $t0
add $t1, $zero, $zero # Zero out $t1
addi $t3, $zero, 1 # load 1 as a mask
sll $t3, $t3, 31 # move the mask to appropriate position
addi $t4, $zero, 32 # loop counter
loop:

and $t1, $t0, $t3 # and the input with the mask
beq $t1, $zero, print # Branch to print if its 0

add $t1, $zero, $zero # Zero out $t1
addi $t1, $zero, 1 # Put a 1 in $t1
j print

print: li $v0, 1
move $a0, $t1
syscall

srl $t3, $t3, 1
addi $t4, $t4, -1
bne $t4, $zero, loop

jr $ra

[RustyBEW]

Post what you've got and what part of it is giving you trouble.

I figured it out:

# Brent Wagner

.data
ask_str1: .asciiz "Enter a number PLEASE: "
result_str: .asciiz ""
.align 2

.text
.globl __start

__start:
# ask and store the first number
li $v0, 4
la $a0, ask_str1
syscall
li $v0, 5
syscall
move $a0, $v0

jal print_bin

# New Line
li $v0, 11
li $a0, 10
syscall

j __start

print_bin:

add $t0, $zero, $a0 # put our input ($a0) into $t0
add $t1, $zero, $zero # Zero out $t1
addi $t3, $zero, 1 # load 1 as a mask
sll $t3, $t3, 31 # move the mask to appropriate position
addi $t4, $zero, 32 # loop counter
loop:

and $t1, $t0, $t3 # and the input with the mask
beq $t1, $zero, print # Branch to print if its 0

add $t1, $zero, $zero # Zero out $t1
addi $t1, $zero, 1 # Put a 1 in $t1
j print

print: li $v0, 1
move $a0, $t1
syscall

srl $t3, $t3, 1
addi $t4, $t4, -1
bne $t4, $zero, loop

jr $ra

[ombadboy]

could someone briefly describe how this MIPS code works please?

i get the syscalls, and the registers and all.. but how does it actually convert the decimal into binary? I cant seem to understand the logic behind it..