Array length

[Tales]

Can someone help me with this?

class Note{
private:
double Freq;
int milisec;
public:
Note();
Note(double Fr, int ms){
Freq = Fr;
milisec = ms;
};
~Note();
};

Ok... now I declare something like this:

Note mynotes[MAX_NOTES];

is there a way to find out the array size?

Thanks

[John A]

>is there a way to find out the array size?
Depends where you need to find such a length.

If the array is in fact being held by a pointer, then no, there isn't a way to figure out the size of an array, because there's boundaries as it's a pointer.

If it is a real array however, you can use the sizeof operator to calculate it by dividing the total amount of memory taken by the array by the size of an element.

#include <iostream>
using namespace std;

int main() {
	int array[10] = {0};
	cout << "Array size is " << sizeof array / sizeof *array << ". " 
             << endl;
}

But then again, why do you need to calculate it anyway? If must have known at some point what the array dimensions were, and surely you can save that number...

[Tales]

Is there a way to return the values of a Note?

I mean something like:

Note Note::getNote(){
return //Note values Freq and milisec
}

[John A]

>Is there a way to return the values of a Note?
Try creating separate accessor functions, as you cannot return more than one value from a function. Something like getFreq , getMillisec , etc..

[vijayan121]

there are two ways to simulate returning
many values from a function:
a. return a struct with more than one
member variable. std :: pair<> is handy
if you want to return a pair of values.
b. pass a modifiable referance (or pointer
to non const) as a parameter, which
the function can fill up.
if the types of all the values returned are
the same, u could also return a collection;
eg: std::vector