Simplified DES

[praneeth_gunda]

Hi EveryBody,This is the Code I have written for Simplified DES it is delivering the Cipher of 16-bit size actually it should deliver of size 8
Please help me in solving the Problem and even tell me how 2 reduce the Complexity

#include<string.h>
char ep[8],p10[10],p8[8],ip[8],ip1[8],pr[10],key1[8],key2[8],p4[4];
int s0[4][4]={{1,0,3,2},{3,2,1,0},{0,2,1,3},{3,1,3,2}}
,s1[4][4]={{0,1,2,3},{2,0,1,3},{3,0,1,0},{2,1,0,3}};
void p10f(char ab[10])
{
 strcpy(p10,"\0");
 p10[0]=ab[2];p10[1]=ab[4];p10[2]=ab[1];p10[3]=ab[6];p10[4]=ab[3];
 p10[5]=ab[9];p10[6]=ab[0];p10[7]=ab[8];p10[8]=ab[7];p10[9]=ab[5];
}
void p8f(char cd[10])
{
 strcpy(p8,"\0");
 p10[0]=cd[5];p10[1]=cd[2];p10[2]=cd[6];p10[3]=cd[3];p10[4]=cd[7];
 p10[5]=cd[4];p10[6]=cd[9];p10[7]=cd[8];
}
void p4f(char lm[4])
{
 strcpy(p4,"\0");
 p4[0]=lm[1];p4[1]=lm[3];p4[2]=lm[2];p4[3]=lm[0];
}

void epf(char ed[4])
{
 strcpy(ep,"\0");
 ep[0]=ed[3];ep[1]=ed[0];ep[2]=ed[1];ep[3]=ed[2];ep[4]=ed[1];
 ep[5]=ed[2];ep[6]=ed[3];ep[7]=ed[0];
}
void ipf(char ef[8])
{
 strcpy(ip,"\0");
 ip[0]=ef[1];ip[1]=ef[5];ip[2]=ef[2];ip[3]=ef[0];ip[4]=ef[3];
 ip[5]=ef[7];ip[6]=ef[4];ip[7]=ef[6];
}
void ip1f(char ef[8])
{
 strcpy(ip1,"\0");
 ip1[0]=ef[3];ip1[1]=ef[0];ip1[2]=ef[2];ip1[3]=ef[4];ip1[4]=ef[6];
 ip1[5]=ef[1];ip1[6]=ef[7];ip1[7]=ef[5];
}
const char* substr(char* pra,int strt,int end)
{
  int j,k=0;
  char *a;
  for(j=strt,k=0;j<=end&&k<=(end-strt);j++,k++)
    a[k]=pra[j];
  return a;
}
const char* leftshift(char* vam,int sid)
{
  int tmp;
  char* chaitu;
  for(tmp=0;tmp<strlen(vam);tmp++)
     chaitu[tmp]=vam[tmp]-sid;
  return chaitu;
}
const char* exor(char* pra,char* div)
{
  int x;
  char* out;
  for(x=0;x<strlen(pra);x++)
  {
    if(pra[x]==div[x])
     out[x]='0';
    else
     out[x]='1';
  }
  return out;
}
void genkey(char keyz[10])
{
 char pra[5],giri[5],raj[5],vasu[5],sri[10];
 strcpy(key1,"\0");
 strcpy(key2,"\0");
 strcpy(pra,substr(keyz,0,4));
 strcpy(giri,substr(keyz,5,9));
 strcpy(raj,leftshift(pra,1));
 strcpy(vasu,leftshift(giri,1));
 strcpy(sri,strcat(raj,vasu));
 p8f(sri);
 strcpy(key1,p8);
 strcpy(pra,substr(key1,0,4));
 strcpy(giri,substr(key1,5,9));
 strcpy(raj,leftshift(pra,2));
 strcpy(vasu,leftshift(giri,2));
 strcpy(sri,strcat(raj,vasu));
 p8f(sri);
 strcpy(key2,p8);
}
int toNumber(char re[2]){
int hi;
if(strcmp(re,"00")==0)
hi=0;
if(strcmp(re,"01")==0)
hi=1;
if(strcmp(re,"10")==0)
hi=2;
if(strcmp(re,"11")==0)
hi=4;
return hi;
}
const char* binary(int ki)
{
char trap[2];
  if(ki==0)
    strcpy(trap,"00");
  if(ki==1)
    strcpy(trap,"01");
  if(ki==2)
    strcpy(trap,"10");
  if(ki==3)
    strcpy(trap,"11");
  return trap;
}
int main()
{
char ptxt[8],key[10],temptxt[8],temptxt1[8],temp[4],
temp2[8],tmpx[2],tmpy[2],temp3[4],outsx,outsy,tmpu[2],
tmpv[2],templ[2],tempr[2],tempq[4],temp4[4],tempw[4],
tmptxt[8],tmpin[4];
int i,j,m,n;
clrscr();
printf("\t");
printf("Enter The Plain Txt of 8 bits");
scanf("%s",ptxt);
printf("Enter the Key(10 bits)");
scanf("%s",key);
genkey(key);
ipf(ptxt);
strcpy(temp,substr(ip,4,7));
strcpy(tempw,substr(ip,0,3));
epf(temp);
strcpy(temp2,exor(ep,key1));
strcpy(temp3,substr(ip,0,3));
strcpy(temp4,substr(ip,4,7));
tmpx[0]=temp3[0];tmpx[1]=temp3[3];
tmpy[0]=temp3[1];tmpy[1]=temp3[2];
i=toNumber(tmpx);j=toNumber(tmpy);
tmpu[0]=temp4[0];tmpu[1]=temp4[3];
tmpv[0]=temp4[1];tmpv[1]=temp4[2];
m=toNumber(tmpu);n=toNumber(tmpv);
strcpy(templ,binary(s1[i][j]));
strcpy(tempr,binary(s1[m][n]));
strcpy(tempq,"\0");
strcat(tempq,templ);
strcat(tempq,tempr);
p4f(tempq);
strcpy(tmpin,exor(p4,tempw));
strcpy(tmptxt,"\0");
strcat(tmptxt,temp);
strcat(tmptxt,tmpin);
strcpy(temp,substr(tmptxt,4,7));
strcpy(tempw,substr(tmptxt,0,3));
epf(temp);
strcpy(temp2,exor(ep,key2));
strcpy(temp3,substr(ip,0,3));
strcpy(temp4,substr(ip,4,7));
tmpx[0]=temp3[0];tmpx[1]=temp3[3];
tmpy[0]=temp3[1];tmpy[1]=temp3[2];
i=toNumber(tmpx);j=toNumber(tmpy);
tmpu[0]=temp4[0];tmpu[1]=temp4[3];
tmpv[0]=temp4[1];tmpv[1]=temp4[2];
m=toNumber(tmpu);n=toNumber(tmpv);
strcpy(templ,binary(s1[i][j]));
strcpy(tempr,binary(s1[m][n]));
strcpy(tempq,"\0");
strcat(tempq,templ);
strcat(tempq,tempr);
p4f(tempq);
strcpy(tmpin,exor(p4,tempw));
strcpy(tmptxt,"\0");
strcat(tmptxt,temp);
strcat(tmptxt,tmpin);
ip1f(tmptxt);
printf("%s",ip1);
return 0;
}

[iamthwee]

Again your code has issues which you need to fix prior to going any further. Having you read the beginner tutorials?

Once you've done that look below:
http://www.tropsoft.com/strongenc/des.htm

[praneeth_gunda]

Please say what r the mistakes i have to fix? PLease Help me i can't trace them out!

[iamthwee]

Please say what r the mistakes i have to fix? PLease Help me i can't trace them out!

As I mentioned before you need to look at the beginner tutorials first...

[haricharanvihar]

its one of the shortest prog i hav ever seen...;)

[Adak]

The best way to simplify a program, is to refer back to your logic you used to create it. That might be your flowchart or pseudo code - or just a diagram on a napkin. Whatever you used to create the logic for this program.

Now ask yourself, "Are there any steps that could easily be combined?", "Do I have any steps that are redundant or unnecessary?".

Before you reach the ability to simplify a solution, you have to go past the understanding you had, when you created the more complicated solution. That seems backwards maybe, but it's true.

First thing, is to be absolutely certain you know what you want in your program. Your first post sounds unsure about 8 or 16 bit encryption. Nail down EXACTLY what you want, and run a small sample through the encryption you want, by hand - with paper and pencil - to be sure you understand it, and the steps for your logic and program, all make sense.

After the above, step through your program with the debugger, and watch the variables as they change. Are they changing as you need them to? Add any print statements you need into the code, but your debugger is your main helper, of course.

Good luck.

[elava]

HI I am student n i am new to programming can any one sugguest me how to write a program for Simplified DES 1 round Encryption ...