i++ and ++i - Page 2

[balu116]

void main()
{
int i=3;
printf("%d,%d,%d",i,i++,++i);
getch();
}
o/p:
5,4,4
if we r using ++i it will increment and it will asign to i so ans is 4
if we r using i++ it will increment but it assign to i so ans is 4
b'coz of i++ i value is 5.for clarifications execute the program

[Narue]

Not only is your example horribly broken, it's not even a valid example of the point you're trying to make.

>void main()
Implementation-defined behavior. main is required to return int.

>printf("%d,%d,%d",i,i++,++i);
Undefined behavior. The commas in an argument list do not constitute sequence points, and ++ modifies its operand.
Undefined behavior. You didn't include stdio.h, and functions that take variable arguments require a prototype in scope.

>getch();
Implementation-defined behavior. You didn't include a header that declares getch, and getch isn't a standard function.

[ChaseVoid]

Haahaa, good one Narue, But hell yeah that example will only give out errors.

Btw, balu116, please use the code tags. Posting source code like that is rude.

[Salem]

When did this become the noob gets it wrong thread?

It seems a magnet for 1-post people to chip in with their "interpretation" only to be corrected for getting some aspect of "side effect" or "sequence point" wrong.

[ChaseVoid]

xD but it can't be helped but corrected. Since others who are new here might get it wrong (which happens a lot). A good code writing practice is always appreciated.

[airsheys]

int i=10;
cout << ++i << i++ << ++i;

using Borland C++, the output will be: 131111
instead of the expected output: 111112

Why is it?

[WaltP]

Try reading the thread.