Hi, its me again. I need help one last time. This time my problem is pretty simple, I just can't find it myself it seems. Please lend some assistance.
Here's my assignment.
Create a program that takes in 2 integers and displays the result of dividing the two integers. This program should prompt for two integers and display the results repeatedly until the user types in -99.
The main method calls another method. The other method contains the prompt and the division. The main method has a try and catch that surrounds the call to the second method. The catch is for a “divide by zero error” (you have to figure out which one that is). When the error is caught, display a message.
import java.util.InputMismatchException;
import java.util.Scanner;
public class DivideByZero
{
public static int quotient( int numerator, int denominator )
throws ArithmeticException
{
return numerator / denominator;
}
public static void main( String args[] )
{
Scanner scanner = new Scanner(System.in );
boolean continueLoop = true;
do
{
try
{
System.out.print( "Please enter an integer numerator: ");
int numerator = scanner.nextInt();
System.out.print( "Please enter an integer denominator: ");
int denominator = scanner.nextInt();
if ( numerator != -99)
{
int result = quotient( numerator, denominator );
System.out.printf( "\nResult: %d / %d = %d\n", numerator,
denominator, result );
continueLoop = false;
}
else
{
continueLoop = true;
}
}
catch ( InputMismatchException inputMismatchException )
{
System.err.printf ( "\nException: %s\n",
inputMismatchException );
scanner.nextLine();
System.out.println( "You must enter integers. Please try again. \n" );
}
catch ( ArithmeticException arithmeticException )
{
System.err.printf( "\nException: %s\n", arithmeticException );
System.out.println( "Zero is an invalid denominator. Please try again." );
}
}while ( continueLoop );
}
}
My problem is that my program will not terminate after inputting -99. Any help, you guys? Thank you in advance.