Member Avatar for a4tech

Hi all,

I am a beginner in using PHP. I have wrote a code that will retrieve the checkbox value after checking from database. Basically, it is a simple search where user has to check the value of checkbox in the form.It then will displaying the result after checking the checkbox that the user have check in database.

Another question, is there possible in php to do datagrid ? What are the steps that are require to do datagrid.


Hope anyone can help me with the problems.

Thank You

<form name="form1" method="post" action="search_with_checkbox_proc.php"> <table width="100%" border="0" bgcolor="#D6E3F7">
<tr>
<td class="text">Your are Expertise field: </td>
</tr>
<tr>
<td class="examplelink">
<input type="checkbox" name="chkexpert[]" value="Java">
Java
<input type="checkbox" name="chkexpert[]" value="PHP">
PHP
<input type="checkbox" name="chkexpert[]" value="ASP">
ASP
<input type="checkbox" name="chkexpert[]" value=".NET">
.NET
<input type="checkbox" name="chkexpert[]" value="JavaScript">
JavaScript</td>


</tr>
<tr>
<td><p>
  <input type="submit" name="Submit" value="Submit">
</p>
  <p>
  
</p></td>
</tr>
<tr>

</tr>
<tr>
<td class="reditalic">&nbsp; </td>
</tr>
</table>
</form>
<?php

// 1. connect with mysql server
$conn = mysql_connect("localhost","root","");

// 2. select the database we will use
mysql_select_db("test_php",$conn);

$checkbox = $_POST['chkexpert'];





$result = mysql_query("select * from register where checkbox =('$checkbox')");

$resultArray = mysql_fetch_array($result, MYSQL_ASSOC);


if(isset($_POST['Submit']))
{
	echo "<h2> Result </h2>";
	
    for ($i=0; $i<count($_POST['chkexpert']);$i++) 
	{		
       //echo "<br />Result $i = ".$_POST['chkexpert'][$i];
	  
	  echo "<br /> ".$_POST['chkexpert'][$i];
    }

}


if($resultArray['chkexpert'] != $checkbox)
{
	echo "There is no record for your search selection";
}




?>
  • 4 Contributors
  • 4 Replies
  • 102 Views
  • 2 Days Discussion Span
  • Latest Post Latest Post by R0bb0b
Member Avatar for nav33n

$checkbox = $_POST;
$result = mysql_query("select * from register where checkbox =('$checkbox')");

You can't do it this way. $checkbox is an array and your query will not return any rows.
You have to go through each element of the array (ie., $checkbox) and then use it in your query.
And I don't know what a datagrid is.

Member Avatar for R0bb0b

A datagrid is simply an html table, modified by css to look pretty and could have added functionality with javascript and ajax for autoupdates and what not. It just depends on what kind of functionality you would like to have in your datagrid.

Member Avatar for harrence

Send some code for us to have a look at.

harrence

Member Avatar for R0bb0b

What do you want to do with it?

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