PHP Statement ?

[gandil]

I have a db query, which show datas from mysql database.
I want to do : ıf number of rows from query is bigger than x do something if small do another thing. Namely;

$qry = mysql_query("SELECT * FROM data_table WHERE page='$page'",$dbh);
$total = mysql_num_rows($qry);

if($total>7)
{
  something...
}

else{
  another thing;
}

but it always going to first statement whatever $total is. I echo the $total. It gives 8.
What is wrong?

[Will Gresham]

The is equates to

if ($total is greater than 7) {
  something...
} else {
  another thing
}

So when total=8 it will select the first one.

[gandil]

if ($total is greater than 7) 
{  
       something...
} 
else 
{  
       another thing
}

I am when total is 1 or 8 whatever is; it is going to same statement. Why?

[Will Gresham]

Try:

if (mysql_num_rows($qry) > 7 ) {
  something...
} else {
 another thing
}

[PoA]

Why don't you use COUNT in sql statement instead?

$qry = mysql_query("SELECT COUNT(*) FROM data_table WHERE page='$page'",$dbh);

[Shanti C]

yes , try PoA way like:

$seq="select count(*) as cnt fromdata_table WHERE page='$page'";
	$sres=mysql_query($seq);
$srow=mysql_fetch_assoc($sres);	
	
	if($srow['cnt']>7) {
	
		//do something}
else if($srow['cnt']<=7)
	{
//do another thing	
	}

[danishbacker]

$qry = mysql_query("SELECT * FROM data_table WHERE page='$page'",$dbh);
while($info = mysql_fetch_array( $qry )) {
   $total++;
}

if($total>7)
{
  something...
}

else{
  another thing;
}

Try this.
i think mysql_num_rows(); will counting all the rows in the table.

but it always going to first statement whatever $total is. I echo the $total. It gives 8.
What is wrong?

[jt1]

Using the COUNT(*) query by PoA or mysql_num_rows on your query will return the same value.