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About Me

EverPeaceFuLL

Interests
Music , Painting & Planting ...
PC Specs
Microsoft Windows 7 Enterprise, AMD Athlon (tm) II X2 245 Processor 2.90 GHz,3 GB of RAM
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hello.. read the following: How to Disable 'View Source' [url]http://www.felgall.com/htmlt4.htm[/url] [url]http://www.encrypt-html.com/_disable_view_source.htm[/url] [url]http://en.allexperts.com/q/Javascript-1520/disable-view-source-1.htm[/url] [url]http://www.15seconds.com/howto/pg000916.htm[/url]

Member Avatar for π™ΉπšŠπšœπš–πš’πš—πšŽοΌˆγƒ€γƒΌγƒͺン)
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helloo... see this link will help you... [url]http://php.bubble.ro/scripts/numbers-words.php[/url]

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this error will occur at the times of: 1.any space is there before the session_start(); function..Means it sholu be the first line of your application... 2.dont use session_start(); as twice (in your main application and in your included application)

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1.A NULL value represents the absence of a value for a record in a field (others softwares call it also a missing value). 2.An empty value is a "field-formatted" value with no significant data in it. 3.NULL isn't allocated any memory, the string with NUll value is just a pointer …

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hello keanan... see this link, will help to solve your problem... [url]http://bestdeveloper.blogspot.com/2008/01/are-getting-spammed-while-sendig-emails.html[/url]

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or try this: [code] SELECT t1.Name, SUM(t1.Salary + t2.Bonus) as Total From tb1 as t1, tb2 as t2 WHERE t1.Name = t2.Name group by t1.Name order by t1.Salary [/code]

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As i understood, see this code: [code] <script type="text/javascript"> function change_send(x) { //alert(x); window.href="page2.php?text="+x; } </script> <html> <p> <table> <tr> <td> Your full name:</td> <td> <input type="text" name="fullname" onChange="change_send(this.value);"></td> </tr> </table> </html> [/code] or come up with clear information.

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So much stuff is there in google.. Use better keywords. [url]http://www.google.co.in/search?source=ig&hl=en&rlz=&q=insert+form+data+into+mysql+using+php&aq=0&aqi=g7g-v3&aql=&oq=insert+form+data+[/url]

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Member Avatar for php2sheik

First you need to register with payment gate way service providers to make it work on your site..Then they will tell you the information for integration..which is not difficult : just send proper values to specified path which differs for different payment gateways..

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And also check for separate tables.. [url]http://www.bigresource.com/PHP-Import-Excel-file-into-MySQL-database-3GCFOrrb.html#r2WzqLkg[/url]

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For web development , dotNet is the best..... Java is heavily used throughout the industry. It is now open source so does not depend on Sun alone anymore. Advantage of Java is that it can run anywhere while Microsoft stuff only runs on MS systems.

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see this link: [url]http://www.daniweb.com/forums/thread139562.html[/url] [url]http://www.pulasthi.info/2008/09/how-to-increase-pr-rank.html[/url] [url]http://www.articlesbase.com/seo-articles/increase-website-traffic-and-google-pr-by-back-links-543028.html[/url]

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Member Avatar for divyakrishnan

After processing the POST page(db insertions), redirect the user to the same page. if you want check for duplicate record in your db table, then try this like: [code] $q=mysql_query("select id from login where username=".$user_name); $count=mysql_num_rows($q); if($count==0) { // your insert code } else { echo "already exists in database."; …

Member Avatar for Szabi Zsoldos
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Hello.. Try this code to update three or more fields in database: [code=php]$qur= "update `users` set `username`='".$_POST['username']."', `password`='".$_POST['password']."', `name`='".$_POST['name']."', `email`='".$_POST['emailid']."', `phone`='".$_POST['phoneno']."', `country`='".$_POST['country']."', `county`='".$_POST['county']."', `city`='".$_POST['city']."', `pincode`='".$_POST['zip']."', `shipping`='".$_POST['shipping']."', `billing`='".$_POST['billing']."', `organisation`='".$_POST['org']."', `fax`='".$_POST['fax']."' where id=".$_GET['id']; mysql_query( $qur) ;[/code] I think it will work properly after this... ShantI

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Member Avatar for Shanti C

Hi All, Im generating some output files(kind of reports) in my reportGenerator class.Acutally im creating then into hard disk and showing them in browser. But i want this scenario to be developed into my project : Want to return the generated file as stream to another class, and show that …

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what to confused.. you can write.. [code] if($current_month==1) { $lastmonth=12; } else { $lastmonth=$current_month-1; } [/code]

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hi happygeek, Greetings.. i want to change my username from Shanti Chepuru to Shanti C Please Change accordingly. Thanks in Advance.

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Sardar tells a girl "Come 2 my house at night, nobody will b there............. Girl goes at night & really nobody was there

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Well , me historical hero is [URL="http://en.wikipedia.org/wiki/Annamayya"][B]Annamayya[/B][/URL]. His full name is Sri Tallapaka Annamacharya from INDIA. He was the official songmaster of the Tirumala Venkateswara Temple. He was one of the first few who opposed the social stigma towards the untouchable castes in his era,with his sankeertanas explaining that the …

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First you need to create a page with .java extension and place this page in java resources folder. For example: [code] public class Test { public void printHello() { System.out.println("Hello world!"); } } [/code] And call this function in jsp like: [code] <% if(request.getParameter("submit") != null) { Test t= new …

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You can execute linux commands within a php script - all you have to do is put the command line in backticks (`). And also concentrate on [URL="http://au2.php.net/manual/en/function.exec.php"]exec()[/URL] , [URL="http://us2.php.net/manual/en/ref.exec.php"]this[/URL] and [URL="http://in.php.net/shell_exec"]shell_exec()[/URL]..

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[QUOTE]This is my chage password script. This works ONLY if all the data fields entered correctly. Otherwise it gives several error messages. (Ex:incorrect username, incorrect pw etc) [/QUOTE] Yes, the fields should not be null, if you enter nothing , then the query will result nothing,so the problem occurs. Please …

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you can do it by giving image name as img1,img2,img3,img4,img4,img5,img6 and so on... and put your adding image code in for loop like: [code] for($j=1;$j<=10;$j++) { //code for image addition and image name should like $_POST['img'.$j] } [/code]

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Member Avatar for Awah Mohamed

you have to pass $q to the function fetch() not $data.. mysql_fetch_array() function only takes resource returned by mysql_query() function. or change your fetch() like this: [code] function fetch($data) { $q = mysql_query($data); mysql_fetch_array($q); } [/code]

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Use this code in your application: [code=php] <? $query="SELECT sub_cat_id, sub_cat_name FROM category"; /* You can add order by clause to the sql statement if the names are to be displayed in alphabetical order */ $result = mysql_query ($query); echo "<select name=category value=''></option>"; // printing the list box select command …

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change this : $return=mysql_query($query,$link); to: $return=mysql_query($query);

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Hey, You can easily develop this by using simple javascript, See the below example : [CODE]<html> <head> <script type="text/javascript"> function ShowRemainingForm(id) { if(id==0) { document.getElementById("inside").style.display="block"; document.getElementById("outside").style.display="none"; } else { document.getElementById("outside").style.display="block"; document.getElementById("inside").style.display="none"; } } </script> </head> <body> <form action="" method="post" name="form"> <p>Indoor or Outdoor : <select name='in_or_out'onchange="ShowRemainingForm(this.value)"> <option value=''>Select one</option> <option …

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i think this code will help you... [code=html] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <script> function generateRow() { var d=document.getElementById("div"); d.innerHTML+="<p><input type='text' name='food'>"; } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <label> <input name="food" type="text" id="food" /> </label> <p> <input name="food" type="text" id="food" /> </p> <p> …

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hello use this code: [code=php] $t="select * from `yourtable` "; $i=mysql_query($t); $row=mysql_fetch_array($i); $n="select * from yourtable where id > '".$row['id']."'"; $p=mysql_query($n); $d=mysql_fetch_array($p);//here you will get next message... $nextid=$d['id']; $previd=$row['id']; [/code] you just pass the $nextid and $previd to your nextpage...

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Wishing you many more happy returns on your birhtday.. Happy BirthDay..

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hello...check this: [code=php] $to = "somw@some.com"; $from = $_POST['email']; $subject = "Resume Details"; $mail_body = "message body"; $fileatt = $_FILES['fileatt']['tmp_name']; $fileatt_type = $_FILES['fileatt']['type']; $fileatt_name = $_FILES['fileatt']['name']; //echo $fileatt; //echo "<br>".$fileatt_type; //echo "<br>".$fileatt_name; //exit; $headers = "From: $from"; if (is_uploaded_file($fileatt)) { // Read the file to be attached ('rb' = read …

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What are the replacements for javescript. I think JQuery in one of the good replacement for jave scripts though it is developed using Java script. I want to know any other like this .. Please give me any link or information on this Thanks in Advance..

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The End.