<?php
$con = mysql_connect("localhost","teachms_fooduse","science0");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("teachms_foods", $con);
$result = mysql_query("SELECT * FROM Foods");
echo "<table border='1'>
<tr>
<th>Name</th>
<th>Shop</th>
<th>Price</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Name'] . "</td>";
echo "<td>" . $row['Shop'] . "</td>";
echo "<td>" . $row['Price] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
Here is my code, i keep getting the error, it does connect to the database, but throws up this: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource-What is it? Can someone fix it please