This is my code - which displays different articles and produces articles as http://www.mysite.com/testpage.php?test=1
<html>
<body>
<?
$i=$_GET['day'];
switch ($i) {
case 1:
include("2.php");
break;
case 2:
include("3.php");
break;
case 3:
include("4.php");
break;
default:
//echo "page not found!!!!";
}
?>
<!--
<? if($_GET['day']==1){ ?>
<?php include("2.php") ?>
<? }else if($_GET['day']==2){ ?>
<?php include("3.php") ?>
<? }else if($_GET['day']==3){ ?>
<?php include("4.php") ?>
<? }else if($_GET['day']==4){ ?>
<?php include("5.php") ?>
<? }else if($_GET['day']==5){ ?>
<?php include("6.php") ?>
<? }else if($_GET['day']==6){ ?>
<?php include("7.php") ?>
<? }else if($_GET['day']==5){ ?>
<?php include("1.php") ?>
<? }else if(!is_numeric($_GET['day']) || $_GET['day']<1){ ?>
<!--invalid id (or page not found)--> -->
<?php
$d=date("D");
switch ($d)
{
case "Mon":
include("2.php");
//echo "Today is Monday";
break;
case "Tue":
include("3.php");
//echo "Today is Tuesday";
break;
case "Wed":
include("4.php");
//echo "Today is Wednesday";
break;
case "Thu":
include("5.php");
//echo "Today is Thursday";
break;
case "Fri":
include("6.php");
//echo "Today is Friday";
break;
case "Sat":
include("7.php");
//echo "Today is Saturday";
break;
case "Sun":
include("1.php");
//echo "Today is Sunday";
break;
default:
//echo "Wonder which day is this ?";
}
?>
</body>
</html>
However, I get this error:
Parse error: syntax error, unexpected $end in C:\www\vhosts\mylocalhostsite\testing.php on line 73
I have tried for myself to fix it, but keep getting the $end error repeatedly, anyone else done this type of PHP and managed to find a fix for this?