It cannot display the value of the checkbox,please tell me what wrong of it!
Thak you
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" c />
<title>Untitled Document</title>
</head>
<body>
<?php
if(isset($_POST["Sumbit"]))
{
$fruit=isset($_POST["apple"]) ? $_POST["apple"]:"";
if(isset($_POST["bananan"]))
{
if(!empty($fruit))
$fruit.=", ";
$fruit.=$_POST["bananan"];
}
if(isset($_POST["orange"]))
{
if(!empty($fruit))
$fruit.=", ";
$fruit.=$_POST["orange"];
}
print"your faviours fruit is:".$fruit;
}
?>
<form id="form1" name="form1" method="post" action="fruit.php">
<label>
<input name="apple" type="checkbox" id="apple" value="apple" />
</label>
apple
<label>
<input name="bananan" type="checkbox" id="bananan" value="bananan" />
banana
<input name="orange" type="checkbox" id="orange" value="orange" />
</label>
orange
<label>
<input type="submit" name="Submit" id="Submit" value="Submit" />
</label>
</form>
</body>
</html>