Image retrieval

[shenbagam]

<?php
$con = mysql_connect("localhost","root","" );
mysql_select_db("test",$con);
$sql="select image from image";
$res=mysql_query($sql) or die(mysql_error());
$i=1;
while($i < mysql_num_rows($res))
{
$image_id[$i] = mysql_result($res, $i);
echo "<img src=\"".$image_id[$i]."\">";
$i++;
}

?>

I'm using this code to display the image from mysql
but images are shown like this
M¢—‡¤6n幆J1³ŒªÌF·æFLùp1 `‘ã:ÃDVNÒ–¢QSgWñg€?´‘íx3²ûEùÝ ô.l%·ËìÈŒÿAzH­'óÀËË€XƒÍ«L²GçÚ›9ást¸°äŒëŸ]˜¦21ŒÖ|¸E^®ÏJOXX&æàߣéü6bêæ¬Öò7aúQ¡·÷9;Ó-ˆ )ôdx¹cüÖlÒ'j( q1ÌnéW4Ó÷dÇå©uF
Any body please help me whats the error in that code:?:

[Dragonbaki]

Images are the special type to handle with Mysql database.. First of all, check if you uploaded the image to the database correcly by the following code as an example..

<?php
    // the upload function
    function upload(){
 
    if(is_uploaded_file($_FILES['userfile']['tmp_name'])) {
 
        // check the file is less than the maximum file size
        if($_FILES['userfile']['size'] < $maxsize)
            {
        // prepare the image for insertion
        $imgData =addslashes (file_get_contents($_FILES['userfile']['tmp_name']));
        // $imgData = addslashes($_FILES['userfile']);
 
        // get the image info..
          $size = getimagesize($_FILES['userfile']['tmp_name']);
 
        // put the image in the db...
          // database connection
          mysql_connect("localhost", "$username", "$password") OR DIE (mysql_error());
 
          // select the db
          mysql_select_db ("$dbname") OR DIE ("Unable to select db".mysql_error());
 
        // our sql query
        $sql = "INSERT INTO testblob
                ( image_id , image_type ,image, image_size, image_name)
                VALUES
                ('', '{$size['mime']}', '{$imgData}', '{$size[3]}', '{$_FILES['userfile']['name']}')";
 
        // insert the image
        if(!mysql_query($sql)) {
            echo 'Unable to upload file';
            }
        }
    }
    else {
         // if the file is not less than the maximum allowed, print an error
         echo
          '<div>File exceeds the Maximum File limit</div>
          <div>Maximum File limit is '.$maxsize.'</div>
          <div>File '.$_FILES['userfile']['name'].' is '.$_FILES['userfile']['size'].' bytes</div>
          <hr />';
         }
    }
?>

You have to upload the images in detail as image size, name, type etc...
And retrieving the image from database also in same manner...

<?php
    // just so we know it is broken
    error_reporting(E_ALL);
    // some basic sanity checks
    if(isset($_GET['image_id']) && is_numeric($_GET['image_id'])) {
        //connect to the db
        $link = mysql_connect("localhost", "username", "password") or die("Could not connect: " . mysql_error());
 
        // select our database
        mysql_select_db("testblob") or die(mysql_error());
 
        // get the image from the db
        $sql = "SELECT image FROM testblob WHERE image_id=0";
 
        // the result of the query
        $result = mysql_query("$sql") or die("Invalid query: " . mysql_error());
 
        // set the header for the image
        header("Content-type: image/jpeg");
        echo mysql_result($result, 0);
 
        // close the db link
        mysql_close($link);
    }
    else {
        echo 'Please use a real id number';
    }
?>

This will work fine.. Still any probs, pls let me know...

[Dragonbaki]

In the above source., at line 19 specifies an header function.. This is very important...