I want to working with login system jQuery ajax and json. I'm facing no problem with success function. I dn't know how to through custom errors like "incorrect login".
Here is my code, Please help me.
<script>
$(document).ready(function(){
$("#login").click(function(){
if($("#defaultEmail").val() == ""){
$("#defaultEmail").addClass("field-err");
$("#defaultEmail").focus();
}else if($("#defaultPassword").val() == ""){
$("#defaultEmail").removeClass("field-err");
$("#defaultPassword").addClass("field-err");
$("#defaultPassword").focus();
}else{
$("#defaultPassword").removeClass("field-err");
$('#loading').css('display', 'block');
var email = $('#defaultEmail').val();
var password = $('#defaultPassword').val();
var queryString = "email=" + email + "&password=" + password + "";
$.ajax({
url: 'secureLogin.php',
contentType: "application/json; charset=utf-8",
dataType:'json',
async: false,
type:'GET',
data: queryString,
success: function(data){
$('#loading').css('display', 'none');
var url = "c_profile.php";
$(location).attr('href',url);
},
error: function(request,error){
$('#loading').css('display', 'block');
$("#log-ajax-error").append("ERROR: " + error);
}
});
}
});
});
</script>
Here is my sucureLogin.php code
$email = $_GET['email'];
$password = $_GET['password'];
$encrypted_pass = md5($password);
$sel = @mysql_query("SELECT `name`, `company`, `cid` FROM `company` WHERE `email` = '$email' AND `password` = '$encrypted_pass'");
$count = @mysql_num_rows($sel);
if($count > 0){
while($data = @mysql_fetch_array($sel)){
// Succes here
}
}else{
$arr = array('a' => 'Unable to login');
echo json_encode($arr);
}
i'm throwing json_encode for the error. Please help me with this. Thanks in advance.