PHP basename

[freakvista]

Hi again. This is the part of the code that doesn't work.

$fileBaseName=basename($file,'.jpg');
echo("<img src='{$handle}/{$file}' alt=$fileBaseName />");

So what i want to do is at alt to show only the name without the.jpg and i dont know why if i have two or three words is stops at the first word, meaning that it stops at the firt " ". So how can i fix this? Tried with explode too, i don't think the basename is to blame for this, but i dont know what to say...

[cereal]

Use pathinfo(): http://php.net/manual/en/function.pathinfo.php

$file = 'test.jpg';
echo pathinfo($file,PATHINFO_FILENAME);

[freakvista]

Sorry i didn't make myself clear. So i have a file in which i read the files(the files are 100% jpg i made sure of that) and i want them to show on the scren with echo

for ($r=1;$r<=$p;$r++){
        if (false !== ($file = readdir($dir))){
            $fileBaseName=basename($file,'.jpg');
            echo("<img src='{$handle}/{$file}' alt=$fileBaseName />");
        }
}

[diafol]

I like glob :) :

$handle = "img/"; //why is this different to the orig path??
foreach (glob("img/*.jpg") as $filename) {
    $file = basename($filename);
    echo "<img src='$handle/$file' />";
}

If $handle is superfluous:

foreach (glob("img/*.jpg") as $filename) {
    echo "<img src='$filename' />";
}

One downside of glob is that it doesn't support pcre regex, so if you want to get case-insensitive 'jpg' and 'jp?g' (for jpeg), then, you could do this:

foreach (glob("img/*.[jJ][pP]*[gG]") as $filename) {

However, that would return files with extensions such as .jpefefeg too! So if you're sure that they're all jpg and not jpeg:

foreach (glob("img/*.[jJ][pP][gG]") as $filename) {

may be better

[freakvista]

there are 10 folders in which there are another 3 other folders so that's why i use $handle to make sure where am i.

$handle = ("countries/$folder/$sfolder");

$folder and $sfolder are known;

$dir = opendir("countries/$folder/$sfolder");

so if i use glob it will work at the img files in this dir?

And i am not using basename for the src, i am using it for alt, because i have a javascript who shows alt in a different way, and i really need its value.

[diafol]

Glob won't traverse subdirs as well, yu can get results of files (and/or dirs) - UNLESS you use braces, e.g. {img,docs,another_folder} - but that's getting silly.

SO you have this sort of structure:

countries
country1
f1
f2
f3
country2
f1
f2
f3
(etc)

I'm assuming you need just the f1-f3 subfolder contents, there are no images in the country1 or country2 (etc) folders themselves, or the parent 'countries' folder.

If so, try this:

foreach(glob("countries/{USA,Brazil,UK,India}/{subfolder1,subfolder2,subfolder3}/*.[jJ][pP]*[gG]", GLOB_BRACE) as $r){
    $b = basename($r);
    echo "<img src='$r' alt = '$b' /><br />"; 
}

Place all the countries into a brace, then the subfolders - I'm assuming the subfolders for each country are named the same.

[freakvista]

Goooood.

And now another question. How can i pass the value of a javascript variable to one of php?

[diafol]

No. You need Ajax to do that. Probably not what you're looking for. You can certainly pass php data into js though. If you need help on this, I suggest starting a new thread as this is a totally different topic. That is, once you've searched this forum and Googled a bit!

[minitauros]

If you want to obtain just the name of the file, you could also do it as follows:

<?php
    $file = 'folder1/folder2/image.jpg';
    $file_name = substr($file, strrpos($file, '/') + 1, strrpos($file, '.') - strrpos($file, '/') - 1);
    echo $file_name; // Will output "image".

[freakvista]

Nononono, so this image think is just a page of my html and i have another page in which i want to do something else. Here's what i did:
-i have a background that changes every 5 seconds, or change by pressing one of left or right button;
-and if you press a button in the center of the page it pop-ups a video - and now i want to make, if a certain file exists(..../javascript_indicator.txt) and if it doesn't i will do something else. All i need is to know how to pass the javascript indicator to php so that i can do certain things. Here's my ajax:

var ajaxRequest;  // The variable that makes Ajax possible!

        try{
            // Opera 8.0+, Firefox, Safari
            ajaxRequest = new XMLHttpRequest();
        } catch (e){
            // Internet Explorer Browsers
            try{
                ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
            } catch (e) {
                try{
                    ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
                } catch (e){
                    // Something went wrong
                    alert("Your browser broke!");
                    return false;
                }
            }
        }
        // Create a function that will receive data sent from the server
        ajaxRequest.open("GET", url, true); 
        ajaxRequest.send(); 

and here is the html code(not all of it) which i think i'll make it ajax.php...

            $cont = ...
            $filec="countries/Video/$cont.txt";
            if (file_exists($filec)) {
                $fh=fopen($filec,'r');
                $ur=fgets($fh);
                echo"<a href=$ur class='winDiv' rel='video'>";
                fclose($filec);
            } else {
                echo"<a href='video.php?blu=$cont' class='winDiv'>";
            }

)

So how can i get the $cont variable to be equal to a cont variable in a javascript function? Forgot to say... in the file in the first line is a youtube url.

[freakvista]

It doesn't matter, i will not use this...

[diafol]

Like I said, this is a different question/topic. Consider a new thread and a descriptive title.