Member Avatar for batoolhussain

hi everyone. how can i upload image using asp.net with vb.net

  • 3 Contributors
  • 3 Replies
  • 229 Views
  • 5 Days Discussion Span
  • Latest Post Latest Post by batoolhussain

Recommended Answers

All 3 Replies

Member Avatar for djjeavons

Hi

You can use the FileUpload control to request the file from the user and then use the SaveAs method to save it to the server. That is assuming that you want to save it to disk and not to a database or something else as you haven't really specified much information.

A quick example would be:

ASPX Page

<body>
    <form id="form1" runat="server">
    <div>
        <asp:FileUpload ID="fileUpload" runat="server" />
        <p>
            <asp:Button ID="uploadButton" runat="server" Text="Upload File" OnClick="uploadButton_Click" />
        </p>
    </div>
    </form>
</body>

Code behind

Protected Sub uploadButton_Click(sender As Object, e As EventArgs)

    'Ensure a file was selected before attempting to read it
    If fileUpload.HasFile Then

        Dim file As String = fileUpload.FileName
        fileUpload.SaveAs(String.Format("{0}{1}", Server.MapPath("~/"), file))

    End If

End Sub

HTH

Member Avatar for tarunap

You can upload the image directly to the database too.

Aspx Page

<asp:FileUpload ID=FileUpload1 runat=server ></asp:FileUpload>

<asp:Button ID="btnUpload" runat="server" Text="Upload"
OnClick="btnUpload_Click" ></asp:Button>
<br />
<asp:Label ID="lblMessage" runat="server" Text=""
Font-Names = "Arial"></asp:Label>

VB.Net Code

Protected Sub btnUpload_Click(ByVal sender As Object, ByVal e As EventArgs)
  ' Read the file and convert it to Byte Array
  Dim filePath As String = FileUpload1.PostedFile.FileName
  Dim filename As String = Path.GetFileName(filePath)
  Dim ext As String = Path.GetExtension(filename)
  Dim contenttype As String = String.Empty

  'Set the contenttype based on File Extension
  Select Case ext
    Case ".doc"
      contenttype = "application/vnd.ms-word"
      Exit Select
    Case ".docx"
      contenttype = "application/vnd.ms-word"
      Exit Select
    Case ".xls"
      contenttype = "application/vnd.ms-excel"
      Exit Select
    Case ".xlsx"
      contenttype = "application/vnd.ms-excel"
      Exit Select
    Case ".jpg"
      contenttype = "image/jpg"
      Exit Select
    Case ".png"
      contenttype = "image/png"
      Exit Select
    Case ".gif"
      contenttype = "image/gif"
      Exit Select
    Case ".pdf"
      contenttype = "application/pdf"
      Exit Select
    End Select
    If contenttype <> String.Empty Then
      Dim fs As Stream = FileUpload1.PostedFile.InputStream
      Dim br As New BinaryReader(fs)
      Dim bytes As Byte() = br.ReadBytes(fs.Length)

      'insert the file into database
       Dim strQuery As String = "insert into tblFiles" _
       & "(Name, ContentType, Data)" _
       & " values (@Name, @ContentType, @Data)"
       Dim cmd As New SqlCommand(strQuery)
       cmd.Parameters.Add("@Name", SqlDbType.VarChar).Value = filename
       cmd.Parameters.Add("@ContentType", SqlDbType.VarChar).Value _
       = contenttype
       cmd.Parameters.Add("@Data", SqlDbType.Binary).Value = bytes
       InsertUpdateData(cmd)
       lblMessage.ForeColor = System.Drawing.Color.Green
       lblMessage.Text = "File Uploaded Successfully"
     Else
       lblMessage.ForeColor = System.Drawing.Color.Red
       lblMessage.Text = "File format not recognised." _
       & " Upload Image/Word/PDF/Excel formats"
     End If
  End Sub



Public Function InsertUpdateData(ByVal cmd As SqlCommand) As Boolean
    Dim strConnString As String = System.Configuration.
    ConfigurationManager.ConnectionStrings("conString").ConnectionString
    Dim con As New SqlConnection(strConnString)
    cmd.CommandType = CommandType.Text
    cmd.Connection = con
    Try
      con.Open()
      cmd.ExecuteNonQuery()
      Return True
    Catch ex As Exception
      Response.Write(ex.Message)
      Return False
    Finally
      con.Close()
      con.Dispose()
    End Try
End Function

Database Table

Field
id int
Name varchar(50)
ContentType varchar(50)
Data varbinary(MAX)

Member Avatar for batoolhussain

thank you very much for reply me.

Edited by batoolhussain
Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.