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I am an 11th grade student in high school.
- Interests
- Star Wars COmbine Gaming Soundboard Operation Lightboard Operation Theatre Tech stuff ^_^
- PC Specs
- I use Code::Blocks v.10.05 and run it on Windows XP Service Pack 3.
 | what he's trying to say is, put smoe 'if' statements in there saying stuff like [code] if(i == 9){cout << "IX";} [/code] and you have to do that for each numeral like that. The best way would probably be to put them in/around the first 'if' statements. Make sense? EDIT: …  |
 | This is my final project for my C++ class online. I was instructed to make a test and to pull answers from withing a .txt file and compare them to the answer that the user inputs. I'm sure there's a much easier wau of doing things than the way I'm … |
| | Re: compiler I do believe this is a repeat thread from over here, under the same title. [URL="http://www.daniweb.com/software-development/cpp/threads/358382"]Here's the link[/URL] programing, try listening to the advice in that thread. |
| | Re: doubles I would try looking into the [icode]<iomanip>[/icode] library using the [icode]fixed[/icode] function. See [URL="http://www.cplusplus.com/reference/iostream/manipulators/fixed/"]Here[/URL]. Or for a more extensive search of the entire library, try looking [URL="http://www.google.com/search?hl=en&source=hp&biw=1131&bih=666&q=C%2B%2B+iomanip&aq=f&aqi=g10&aql=&oq="]here.[/URL] ;) |
| | I have another problem... Let's start with said code: [code] #include <iostream> #include <fstream> //I have tried using fstream.h like my teacher instructs me to do/ #include <cstdlib> //but it gives me another error: see below, in actual post. using std::cout; using std::cin; using std::ios; using std::endl; //using namespace std; … |
| | I have said program: [code] #include <iostream> #include <fstream.h> #include <conio.h> using std::cout; using std::cin; using std::ios; using std::endl; int main() { char first[6]; char middle[16]; char last[16]; int counter = 0; char temp; cout << "Please enter your first, middle, and last name:\n>"; cin.get(first, 6); cin.ignore(80,'\n'); cin.ignore(80, ' '); … |
| | if you want 'a' and 'b' to be able to hold more than one character, then change them to something like this: [code=C++] char a[x] //where x is any number you choose. char b[y] //where y is any number you choose. [/code] as for the 3 attempts before a fail …  |
| | Ok. Listen to everybody here. [b]LISTEN[/b] to them and actually [b]do some work[/b]. Once you have some code proving that you've listened to them, maybe then you'll start seeing what they're talking about ;) This isn't a place full of free answers, it's a place for you to come to … |
| | Ok, so this is going to be a basic question that I should probably know, but it's baffling me right now... Also, be prewarned that this is a homework assignment I'm working on. I don't want answers, just guidance. I understand what I need top do(for the most part. obviously … |
| | [url]http://www.codeblocks.org/downloads/binaries/[/url] ^^THat should get you to the download site for C::B. don't use Dev C++ as I'm required to use it for my class. it sucks, and so I use Code::Blocks behind my instructor's back, since she's unwilling to use anything else. I highly reccommend this IDE to anyone who … |
| | Re: Menu Order So here I was sitting in my high school online C++ Class. I was bored and was trying to work out your problem... and all f a sudden I accidentally type '11' My computer starts freaking out and beeping(not usually a good sign...) and my instructor asks what's going on... … |
| | Re: Input validation sha11e, you may look into the cin.good(), cin.bad(), and/or the cin.fail() commands. I believe those could help you here. YOu could have it set up to say something like: [code] if(cin.fail(variable)) { //do this } else { //do that } [/code] I'd look into that, maybe. It may help. :) |
| | Ok, so I have a stupid question to ask, and I aks all of you not to ridicule one who is merely looking for knowledge. What is the difference between using [code]#include "whatever"[/code] versus using [code]#include <whatever> [/code]? I've always used the brackets versus the quotes, and have tried looking … |
| | Hello, I was working with my C++ homework, and I wanted to combine a couple of projects. Now I've never done anything with project-projects before... it's all been one-file console applications in single "*.cpp" files. Well, I tried my hand at combining two projects into one project file, so I … |
| | Your character array does not have an assigned size, (and someone correct me if I'm wrong) but I believe that when you press enter after typing your name, the '\n' character stays in the inpout stream, causing all of the other questions to be skipped. here's how I solved the … |
| | Okay, so I have said code: [code] #include <iostream> #include <cstdlib> using std::cout; using std::cin; using std::endl; int main() { char input[8]; int counter = 0; int newletter; do { cout << "Please enter a 7 letter word to encrypt:\n>"; cin >> input; if(input[8] != '\0') { input[8] = '\0'; … |
 | First off, please use code tags. Second off, in your code here: [code] while(i>=3){ cout<<" "<<i; [B]i--;[/B] } [/code] you are only decrementing by one. You seem to want to start yuor decrement at 25, and then subtract the decrement by 3 each time (i.e. subtract 25; subtract 22; subtract … |
| | Someone correct me if I'm wrong, but you would need to use a series of for loops, correct? Consider the following program: [code=c++] #include <iostream> #include <cstdlib> using std::cout; int main() { int i,j,k,l,m; cout << "i j k l m\n"; for (i = 0; i <= 1; i++) for … |
| | Hello, my name is not Derek Elensar, but I prefer not t reveal my real name onlin if I can help it... so you can just call me Derek. :) I am a beginner C++ programmer. I'm trying to learn Ruby, but haven't gotten far, as I haven't had much … |
| | Okay. I have said code: [code=C++] #include <iostream> int main() { std::cout << "This is a native C++ program\n" << std::endl; return 0; }//main [/code] How would I compile this from a standard DOS command line? I've searched all over google, and have yet to find an answer that explains … |