A spindle is formed by revolving the region bounded by the graphs of
y= (1/4)*[1+2e^(-x/8) *sin^(2) *((Pi*x)/4)], y=0,x=0,x=8.
About the x-axis. Determine the volume of the spindle.
Please show me how to do this?
A spindle is formed by revolving the region bounded by the graphs of
y= (1/4)*[1+2e^(-x/8) *sin^(2) *((Pi*x)/4)], y=0,x=0,x=8.
About the x-axis. Determine the volume of the spindle.
Please show me how to do this?
To determine the volume you use this formula general volume formule
where:
h = any dimension of the figure,
A(h) = area of the cross-sections perpendicular to h described as a function of the position along h. a and b are the limits of integration for the volumetric sweep.
(This will work for any figure if its cross-sectional area can be determined from h).
check wiki for more info. What are you having problem with? The formation of the integral?
> sin^(2) *((Pi*x)/4)
Lolwut?
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