If I have these function variables:
int (*f)(int);
int (*g)(int);
int (*h)(char);
why can I do the assingment f=g but if I do h=g the C compiler gives me warning while the C++ compiler gives me an error.
Can any one please explain this to me.
vladdy191 0 Newbie Poster
freudian_slip 1 Light Poster
Didn't you post the same topic before? The answer is like two pages behind. h is char but g is int. they are not of the same type.
vladdy191 0 Newbie Poster
Didn't you post the same topic before? The answer is like two pages behind. h is char but g is int. they are not of the same type.
Yes I did but I'm trying to get at why the C compiler gives only a warning while a C++ gives an error.
freudian_slip 1 Light Poster
I think it is because C is just more flexible when it comes to handling memory.. hence giving your more control over it.
[edit] Another thing I can think of is that char is one byte while int is four. C++ compiler probably catches that as an error to prevent such assignment. but since C is naturally more flexible with memory/pointer, it's just an error? Well, maybe I'm just talking out of my ass..
Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
C and C++ are not the same language, so don't expect C compilers to act the same as c++. There are many differences that you will encounter.
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