Hi,
Is this valid in C++??
struct A{...};
class B: public A{...};
Thanks!
In C++ A Struct IS a Class. The only difference is that in a class, the members by default are private. In a Struct, they are by default public.
class base
{ protected:
struct node{};
};
class derived :public base
{
struct node *prev;
};
when i do this i 'm getting an error that prev is not a member of base::node.
what can i do if i want to declare an additional variable
of struct node type in class derived
richard bach, when I compile exactly what you have, i don't get a problem.
Using Visual Studio 2008. V.9.021022.8
#include <iostream>
using namespace std;
class base
{ protected:
struct node{};
};
class derived :public base
{
struct node *prev;
};
class A
{
public:
int a;
};
struct B : A { };
struct C
{
public:
int c;
};
class D : public C { };
int main()
{
B b;
D d;
b.a = 1;
d.c = 2;
cout << b.a << " " << d.c << endl;
}
I compile that and no errors, and I do actually get the numbers.
I don't know to what extend this works, but to this, it is working.
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